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IgorLugansk [536]
3 years ago
9

Any know the answer to this? f(x) =0x+5

Mathematics
1 answer:
enyata [817]3 years ago
3 0
Y=0x+5 this is the answer
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Sinplify by using properties (-2/9) × 1/7 - 3/14 × 1/9 + (-2/9) × 1/14​
irina [24]

Answer:

should be -1/14

Step-by-step explanation:

4 0
3 years ago
I need help plz!!!!!!
GrogVix [38]

Answer:

put -2 in -2    /   put -2 again in same spot and again just do it for 3 times then 1/3 in the middle of 0 and -2 but a bit closer to the -2

Step-by-step explanation:

8 0
3 years ago
The line through (6, 1) and (-3, 5) in slope intercept form
Nikolay [14]

Answer:

y=-4/9x+11/3

Step-by-step explanation:

Reminder: slope intercept form is y=mx+b where m= slope and b=y intercept

Two points are given; (6,1) and (-3,5)

First, find the slope

Reminder: slope is y2-y1/x2-x1

You can plug the numbers given into the equation to get 5-1/-3-6 which equals 4/-9

Now, we can use slope point form which is y-y1=m(x-x1)

Once again, plugging the numbers in (any one of the two points will work) will get

y-1=4/-9(x-6)

Simplifying it will get y=-4/9x+11/3.

8 0
3 years ago
What is the product of −225 and −356 ? −915 −6730 613 ​ 915 ​
Sunny_sXe [5.5K]

Hello from MrBillDoesMath!

Answer:

 80,100  (which is NONE of the provided answers)

Discussion:

-225 * -356 =

+ (225 * 356)   =            as the product of two negative numbers is positive

 80,100


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


7 0
3 years ago
Read 2 more answers
Find the particular solution of d2y/d x2<br> +4.<br> dx/Dy<br> +4y= 2 cos²x
Artyom0805 [142]

The solution to the equation are as follows.

y = c₁e^{\sqrt{-3 -sin²(x)x} } + c₂                e^{\sqrt{-3 -sin²(x)x} }

What is differential equation?

In arithmetic, a equation is associate equation that relates one or a lot of unknown functions and their derivatives.

Main body:

Find the first derivative.

dy/dx=re^{rx}

Find the second derivative.

d²y/dx² =r² e^{rx}

Substitute into the differential equation.

r²e^{rx}+4e^{rx}=cos ²x

Factor e^{rx}out of r²e^{rx}.

e^{rx}r²+4e^{rx}=cos²x

Factor e^{rx} out of 4e^{rx}.

e^{rx}r²+e^{rx}⋅4=cos²x

Factor out of e^{rx}r²+4e^{rx}

e^{rx}(r²+4)=cos²x

Since exponentials can never be zero, divide both sides by

e^{rx}r²+4=cos²x

Use the double-angle identity to transform

cos²x to 1−sin²(x).

r² +4=1−sin²(x)

Subtract 4 from both sides of the equation.

r²=1−sin²(x)−4

Simplify the right side.

r² = -3 -sin²x

r = √-3 -sin²x

By the principle of superposition, the general solution is a linear combination of the two solutions for a second order homogeneous linear differential equation.

y = c₁e^{\sqrt{-3 -sin²(x)x} } + c₂

Hence the differential solution is as follows.

To know more about differential equation , visit:

brainly.com/question/1164377

#SPJ1

6 0
2 years ago
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