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3 years ago

What does 5/12+23/10=

Mathematics

1 answer:

Serhud [2]3 years ago

4 0

Answer:

PEMDAS

(5/12) +(23/10)

5/12=0.42

23/10=2.3

0.42+2.3=2.72

2.72 is the correct answer

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a job offer with a starting salary with $ 35,600 and a guaranteed raise of $ 1200 per year for the next 5 years. what is the tot

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He'll make $41,600 by the sixth year

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3 years ago

What is the answer to this question?<br> 6x - 6 < 12

rosijanka [135]

Answer:

X<3

Step-by-step explanation:

6x−6+6<12+6

6x<18

Step 2: Divide both sides by 6.

6 divded by 6 = 1

18 divided by 6= 3

therefore the answer would be

X<3

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3 years ago

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What is the least common multiple of 3 and 2?

vovikov84 [41]

Answer:

The answer is 6

Step-by-step explanation:

Hope this helps

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3 years ago

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I need help with this one I’m not sure if I got it right

weqwewe [10]

Answer:

144 feet

Step-by-step explanation:

Since this is a quadratic equation, we simply need to find the vertex in order to determine the maximum height!

To solve the equation, follow these steps!:

$0 = 16t^2+96t\\\\\frac{-b}{2a} =x\\\\\frac{-96}{2(-16)}=3=x$

Now we insert x back into the equation...

$= -16(3)^2+96(3)\\ = -16(9)+288\\ =-144+288\\=144$

7 0

2 years ago

Hw 28 shades figure

ra1l [238]

Answer:

Prat 9) $SF=2, x=16\ in$

Part 10) $SF=0.5, x=14\ ft$

Part 11) $SF=0.5, x=3.5\ ft$

Part 12) $SF=3, x=7\ m$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

SF-----> the scale factor

a----> area of the shaded figure

b----> area of the unshaded figure

$SF^{2} =\frac{x}{y}$

Problem 9) we have

$a=216\ in^{2}$

$b=54\ in^{2}$

substitute in the formula

$SF^{2}=\frac{216}{54}$

$SF^{2}=4$

$SF=2$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(2)(8)=16\ in$

Problem 10) we have

$a=161\ ft^{2}$

$b=644\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{161}{644}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(28)=14\ ft$

Problem 11) we have

$a=10.5\ ft^{2}$

$b=42\ ft^{2}$

substitute in the formula

$SF^{2}=\frac{10.5}{42}$

$SF^{2}=0.25$

$SF=0.5$ ------> the scale factor

To find the value of x, multiply the length of the unshaded figure by the scale factor

$x=(0.5)(7)=3.5\ ft$

Problem 12) we have

$a=4,590\ m^{2}$

$b=510\ m^{2}$

substitute in the formula

$SF^{2}=\frac{4,590}{510}$

$SF^{2}=9$

$SF=3$ ------> the scale factor

To find the value of x, divide the length of the shaded figure by the scale factor

$x=(21)/(3)=7\ m$

4 0

3 years ago