All categories

3 years ago

What does 5/12+23/10=

Mathematics

1 answer:

Serhud [2]3 years ago

4 0

Answer:

PEMDAS

(5/12) +(23/10)

5/12=0.42

23/10=2.3

0.42+2.3=2.72

2.72 is the correct answer

You might be interested in

What is the tenth term in the sequence?

Anarel [89]

Answer is 5 , you substitute the letter n with the term position which in this case is tenth

Mark as brainleast plzzz

5 0

3 years ago

You and your friends have decided to camp for a night. Your friend claims the perimeter of his tent is 7.5 metres.

Georgia [21]

Perimeter =8.2
the friend is incorrect

4 0

3 years ago

Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va

Burka [1]

Answer:

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

The polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

$\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)$

with

$\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}$

for some c in the interval (-x, x)

In the particular case f

f(x)=cos(x)

we have

$\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)$

therefore

$\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0$

and the polynomial approximation of T5(x) of cos(x) would be

$\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}$

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

$\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}$

for some c in (-x,x). So

$\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}$

and we must find the values of x for which

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652$

Working this inequality out, we find

$\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815$

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0

3 years ago

Solve the system of equations. 2x + 3y = 1 y = 3x + 15

MrMuchimi

Since y=3x+15
sub 3x+15 for y in other equation

2x+3(3x+15)=1
2x+9x+45=1
minus 45
11x=-44
divide 11
x=-4

sub
y=3x+15
y=3(-4)+15
y=-12+15
y=3

(-4,3)

6 0

3 years ago

Question 9 What is the circumference of a circle whose diameter is ? 2

ZanzabumX [31]

6.28 because pi x diameter = circumference.

( diameter = half of a circle)

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers