All categories

3 years ago

Please help me with questions 14 and 15

Mathematics

1 answer:

Likurg_2 [28]3 years ago

8 0

Problem 14: The answer is choice A since the x coordinate flips in sigh (from positive to negative or vice versa). The y coordinate stays the same. This rule reflects the figure over the y axis.

---------------------------------------------------------------------------------------------

Problem 15: The answer is choice A
cos(angle) = adjacent/hypotenuse
cos(B) = BC/AB
cos(B) = 12/13

You might be interested in

What type of number is −0.5/ −0.5

Ede4ka [16]

Answer:

$\frac{ - 0.5}{ - 0.5} = 1 \\$

1 is a whole number, an integer, and rational.

Step-by-step explanation:

HOPE THIS HELPS.

7 0

2 years ago

Matthew sorts some figures. He includes a regular hexagon with only figures 2 and 3.

kykrilka [37]

Answer:

Step-by-step explanation:

A regular hexagon, a rectangle, and a regular parallelogram all have at least 2 pairs of parallel sides. The sides opposite of each other are parallel. A trapezoidal only has one pair of parallel lines and a kite has 0 parallel sides.

3 0

3 years ago

What is 6,242 ÷ 4 help me please i really dont get it

coldgirl [10]

6242 divided by 4 equals 1,560.5

8 0

3 years ago

Read 2 more answers

What is the perimeter of the figure? <br> 88 in. <br> 88 11/24in.<br> 88 7/8in. <br> 89 7/8i n.

DochEvi [55]

Answer:

The perimeter is 89 7/8 or 89.875

Step-by-step explanation:

You can rewrite each fraction in decimal form

20 9/16 is the same as 20.5625, 23 3/8 is 23.375, 24 5/8 is 24.625, and 21 5/16 as 21.3125. Next, you add them. 20.5625+23.375+24.625+21.3125=89.875

8 0

3 years ago

An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn from the ur

tatuchka [14]

Answer:

(a)10 Outcomes

(b) $\dfrac{2}{5}$

Step-by-step explanation:

An urn contains two blue balls (denoted $B_1 \:and\: B_2$ ) and three white balls (denoted $W_1, W_2 \:and\: W_3$ ).

In the selection, a ball is picked and replaced.

The possible outcomes of the experiment are:

$B_1B_1,B_1B_2,B_1W_1,B_1W_2,B_1W_3\\B_2B_1,B_2B_2,B_2W_1,B_2W_2,B_2W_3\\W_1B_1,W_1B_2,W_1W_1,W_1W_2,W_1W_3\\W_2B_1,W_2B_2,W_2W_1,W_2W_2,W_2W_3\\W_3B_1,W_3B_2,W_3W_1,W_3W_2,W_3W_3$

(a)If the first ball drawn is blue. the outcomes are:

$B_1B_1,B_1B_2,B_1W_1,B_1W_2,B_1W_3\\B_2B_1,B_2B_2,B_2W_1,B_2W_2,B_2W_3$

There are 10 outcomes if the first ball drawn is blue.

Probability that the first ball drawn is blue

$=\dfrac{10}{25}\\ =\dfrac{2}{5}$

4 0

3 years ago