Please help me!!!!! ;))

PLZ HELP MEEEEE!!!! ILL GIVE YOU BRAINLY!!

valkas [14]

Answer:

Step-by-step explanation: -13, 9

8 0

3 years ago

I have underlined the volume of water needed (left) and the volume of chemicals needed (right). How much of the chemical would I

makkiz [27]

3.2 I do believe....

8 0

3 years ago

What is the Square root of -48 ?

antiseptic1488 [7]

6.93
pls mark brainliest

5 0

3 years ago

I'm a father and honestly forgot how to math and was wondering how I'd show my daughter how to do the math problem 354÷2 also ha

matrenka [14]

Answer:

177

Step-by-step explanation:

177

____

2/354

7 0

3 years ago

Read 2 more answers

According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random

Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.39, n = 100$

Then

$s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488$

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean $\mu = 0.39$ and standard deviation $s = 0.0488$

5 0

3 years ago