Answer:
(1.37) AUB = { 1,2,3,4,5,6}
(1.38) AUC = { 1,2,3,4,5 }
(1.39)BUC = { 1,2,3,4,5,6}
(1.40) { 2,4 }
(1.41) { 1,3,5 }
(1.42) { phi }
(1.43) AU(BUC) = { 1,2,3,4,5,6 }
(1.44) { phi }
(1.45) {1,2,3,4,5}
(1.46) { 1,2,3,4,5 }
Running burns the most calories folwed by aerobic
so max out the most and min the least
most running
running has no limit, so see least
aerobic, aerobic has to be at most 30 (less than 30)
rowing has to be at least 15 mins
say row=15 mins
then you have 45 mins left
max out on running (minus 1 tho to do running)
so
44mins running 1 min run, 15min row
total calories=507 calories burned
the way to do it is
x=running minutes
y=aerobic minutes
z=rowing minutes
x+y+z=60
9x+6y+7z=max calories
x≥5
y≤30
z≥15
those are the equations
not sure what the objective function is
Answer:
X = 7 Y = -19
Step-by-step explanation:
If you want to solve this equation by substitution then you have to put the second equation in, so it will look something like this
5x + 1(2-3x)=16
Apply distributive property to solve.
Once you find x, plug it in to find y
To double check your work, you can plug the coordinated values back in
-19 = 2 - 3(7)
-19 = 2-21
This is true, so our solution is correct.
Hope this helps :)
