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levacccp [35]
3 years ago
5

Help asap will mark brainliest

Mathematics
2 answers:
Harrizon [31]3 years ago
8 0

Answer:

Step-by-step explanation:

7-5

-21-0

-2/21. the y intercept would be 5, considering the x is 0 on the first pair of coordinates. so y=-2/21x+5, or A

ki77a [65]3 years ago
7 0

Answer:

y = -2/21(x)+5

Step-by-step explanation:

We know that the formula to find the slope of an a line y = mx + b where m is the slope and b is the y-intercept.

The formula of slope is m = (y2-y1)/(x2-x1)

Using the two points given, we can find the slope:

m = (7-5)/(-21-0)

m = -2/21

b = 5 because (0,5) is the y-intercept

y = -2/21(x)+5

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8^(x-3)=16^(3x+1) solve
rusak2 [61]

Answer:

x = -13/9

Step-by-step explanation:

Solve for x over the real numbers:

8^(x - 3) = 16^(3 x + 1)

Hint: | Take logarithms of both sides to turn products into sums and powers into products.

Take the natural logarithm of both sides and use the identity log(a^b) = b log(a):

3 log(2) (x - 3) = 4 log(2) (3 x + 1)

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides by log(2):

3 (x - 3) = 4 (3 x + 1)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the left hand side:

3 x - 9 = 4 (3 x + 1)

Hint: | Write the linear polynomial on the right hand side in standard form.

Expand out terms of the right hand side:

3 x - 9 = 12 x + 4

Hint: | Isolate x to the left hand side.

Subtract 12 x - 9 from both sides:

-9 x = 13

Hint: | Solve for x.

Divide both sides by -9:

Answer: x = -13/9

4 0
2 years ago
Assuming the weights are in kilograms, what is the mystery weight of y Use the equation you created in part A to find the
Alina [70]

The Answer To Your Question is 1/2

4 0
3 years ago
If quadrilateral ABCD rotates 90° counterclockwise about the origin, what are the coordinates of A′ in quadrilateral A′B′C′D′ ?
Vesna [10]

Answer:

Option B is correct.

The coordinate of A' is (-2 , -1)

Explanation:

The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).

Rotation means moving the shape  around a fixed point clockwise or anticlockwise, and by a certain number of degrees.

Rule for 90° counterclockwise rotation about the origin: (x,y) \rightarrow (-y,x)

or we can say that switch x and y in the coordinates and make y value opposite.

Then, the coordinate of A' :

A(-1,2) \rightarrow A'(-2 ,-1)

Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)


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