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eimsori [14]
3 years ago
7

Solve the system of equations: y = 2x - 4 y = x2 - 4

Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

y=2x-4

Step-by-step explanation:

y=x2-4

ygjn bcgh ccfjm kbhh

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PLEASE HELP ME PLEASE HELP ASAP THANKS (brainlest)
zloy xaker [14]

Answer:

0.999 units

Step-by-step explanation:

D=

\frac{3.14}{\pi}

D=0.9994930426

4 0
3 years ago
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A set of exam scores is normally distributed and has a mean of 80.2 and a standard deviation of 11. What is the probability that
ZanzabumX [31]

Answer:

93.32% probability that a randomly selected score will be greater than 63.7.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80.2, \sigma = 11

What is the probability that a randomly selected score will be greater than 63.7.

This is 1 subtracted by the pvalue of Z when X = 63.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{63.7 - 80.2}{11}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

93.32% probability that a randomly selected score will be greater than 63.7.

5 0
4 years ago
What plus 35 equals 180
Katarina [22]
145. u take 180 subtract 35. It will gives u 145
4 0
3 years ago
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So say selling a backpack thats used-like new and the original price is $54.00 how much should I set the price at??
Nat2105 [25]

it most be eleven hundred

6 0
3 years ago
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X+x+x+x-20 what expression is equivalent to it?
igor_vitrenko [27]
X + x + x + x - 20 is equivalent to 4x - 20 because you can add the like terms, or the x's.
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3 years ago
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