Someone pls help with question 1
1 answer:
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Answer:
Correct option is
b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.
Step-by-step explanation:
Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.
The foot S of PS is on the line RQ.
First of all, let us do a construction here.
Join the point R with P and P with Q.
Please refer to the attached image.
Now, let us consider the triangles PQS and PRS:
- Side QS = RS (as given)
- Side PS = PS (Common side in both the triangles)
Now, Two sides and the angle included between the two triangles are equal.
So by SAS congruence we can say that
Therefore, the corresponding sides will also be equal.
RP = QP
RP is the distance between R and P.
QP is the distance between Q and P.
Hence, to prove that P is equidistant from R and Q, we have proved that:
b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.
Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
See attachment for complete question
Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
when
For bacteria B, we have:
Substitute 0 for x
So; when x = 0
and
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
