Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
If the dimensions are "nice" factors of the quadratic, and if y > -3, we have
.. area = (y +3)(y +5)
y+5 is greater than y +3, so we take the width to be ....
.. width = y+3
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
A full rotation is 360 degrees, divide 360 by the rotation given in the problem:
360 / 120 = 3
A triangle has 3 inside angles, so the answer would be an equilateral triangle.
<h3>
Answer:</h3>
We know that,
<u>Area of rectangular bulletin = L × B</u>
- L × 50 = 45
- L = 45/50 = 9/10cm
<u>Hence, Length of rectangular bulletin is 0.9cm</u>.
