Area of semicircle = 1/2 the area of a circle:
![A_{sc}=\frac{1}{2} \pi r^{2}](https://tex.z-dn.net/?f=%20A_%7Bsc%7D%3D%5Cfrac%7B1%7D%7B2%7D%20%20%5Cpi%20%20r%5E%7B2%7D%20)
radius is half the diameter of 6ft.
![A_{sc} = \frac{1}{2} \pi (3^{2} )=14.13 ft^{2} .](https://tex.z-dn.net/?f=%20A_%7Bsc%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Cpi%20%20%283%5E%7B2%7D%20%29%3D14.13%20ft%5E%7B2%7D%20.)
Area of the rectangle:
![A_{r} =lw=15*6=90 ft^{2} .](https://tex.z-dn.net/?f=%20A_%7Br%7D%20%3Dlw%3D15%2A6%3D90%20ft%5E%7B2%7D%20.)
Add the two together:
90 + 14.13 = 104.13
Round to the nearest tenth (one decimal place)
Area = 104.1 square feet.
Answer:
D
Step-by-step explanation:
Up 2 units = y shifted up by 2:
y = x^2 + 2
to the right 3 units = x shifted right (+) by 3:
y + 3 = x^2 +2
new equation:
y = x^2 - 1
Answer:
Step-by-step explanation:
y + 4 = -8(x - 2)
I dont know the statements that u have but maybe I can guess one...or two
slope = -8
points used were : (2,-4)
y + 4 = -8(x - 2)
y + 4 = -8x + 16
y = -8x + 16 - 4
y = -8x + 12 ............slope intercept form
8x + y = 12 .......standard form
x intercept = (3/2,0)
y intercept = (0,12)
any of that answer ur question ?