Answer:
A. 15
Step-by-step explanation:
To solve this you need to compare the lengths given to you in the question statement.
Because the lines originate from a single point, they're like triangles. We can easily see a triangle AGF and a triangle ADE, right?
Both triangles are similar triangles, so we can see triangle ADE as a larger version of angle AGF.
They give you the dimension of A F and A E (through A F + F E) to establish a ratio... and they give you A G, asking for A D.
So, A F = 16, A E = 20 (16 + 4), A G = 12.
Since A D is to A G what A E is to A F, we can easily make the following cross-multiplication:
So, A D = (A G * A E)/A F
A D = (12 * 20) / 16 = 15
It is 484 m^2 ,to my understanding!
Given that plane P is parallel to the planes containing the base faces of the prism; then, if the plane meets the prism between the planes containing the hexagonal bases, then P meets the prism in a hexagonal region that is congruent (with the same size) to the bases of the prism.
I'm guessing that there must be an equation to go along with this question.
Without it, we don't know what equation Monroe is graphing.
If the equation is [ y = -4/9 x ], then 'A' and 'D' are the points
that lie on the graph of his equation.
If the equation is [ y = -9/4 x ], then 'B; and 'C' are.