Answer:
its c
Step-by-step explanation:
To make this situation easier to understand, you must simplify these fractions. 3/6 is equal to 0.5
6/6 is equal to 1
4/6 is equal to 0.3333 repeating.
With this info we can tell that Gina's sailboat went to longest distant in the fifteen minutes.
Hope this helps! :)
(a) We have ⌊<em>x</em>⌋ = 5 if 5 ≤ <em>x</em> < 6, and similarly ⌊<em>x</em>/3⌋ = 5 if
5 ≤ <em>x</em>/3 < 6 ==> 15 ≤ <em>x</em> < 18
(b) ⌊<em>x</em>⌋ = -2 if -2 ≤ <em>x</em> < -1, so ⌊<em>x</em>/3⌋ = -2 if
-2 ≤ <em>x</em>/3 < -1 ==> -6 ≤ <em>x</em> < -3
In general, ⌊<em>x</em>⌋ = <em>n</em> if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
Answer:
y = 3/2
Step-by-step explanation:
5(2y - 1) - 2(3y) = 1
First we use distributive property:
10y - 5 - 6y = 1
because 5 × 2y = 10y
and -2 × 3y = -6y
Now we combine the like terms:
4y -5 = 1
because 10y - 6y = 4y
Now we have to send the -5 to the other side. (when we send it to the other side it becomes positive because right now it is negative)
4y = 1 + 5
Again we combine the like terms:
4y = 6
(because 5 + 1 = 6)
Now we have to send the 4 to the other side because we need to get the y value. (when we send it to the other sidr it will be divided)
y = 6/4
and we simplify:
y = 3/2
And we cannot simplify or do anything else. So that is the answer.
Hope that helped!
Given: Alonzo's suitcase can weigh no more than 20 kilograms if he wants to take it on the airplane without paying a fee.
Let x denote the weight of suitcase, then
We know that 1 kg =10 hg
Therefore, 20kg=
⇒
Since, the weight of his suitcase is 220 hg.
The amount of weight will Alanzo have to take out of his suitcase to meet the weight limit will be :-
Hence, 20 hg of weight have to take out of his suitcase to meet the weight limit.