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3 years ago

How many times larger ? Is 1.815x10^3 and 4.975x10^12??????

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

4 0

For this case we have the following data:

Debt in September 2015: $1.815 * 10^{13}$

Debt in September 2005: $4.975 * 10^{12}$

The debt in September 2015 can be rewritten as follows:

$18.15 * 10^{12}$

In this way, we divide the 2015 debt between the 2005 debt, obtaining:

$\frac{ 18.15 * 10^{12}}{ 4.975 * 10^{12} }=3.65$

Thus, the 2015 debt is 3.65 times larger than the 2005 debt.

Answer:

3.65 times larger

Scorpion4ik [409]3 years ago

3 0

4975000000000-1815=4974999998185

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svetoff [14.1K]

Answer: 23

Step-by-step explanation:

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2 years ago

Melissa and Brian are at the base of a mountain. Melissa hikes to

Free_Kalibri [48]

67 meters because if you use the triangle congruent method with the altitude at 65 degrees you should get the right answer

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3 years ago

Jean bought a $1,980 snow thrower on the installment plan. The installment agreement included a 10% down payment and 18 monthly

enyata [817]

Answer:

Jean paid $2,286 for the snow thrower, with a finance charge of $306.

Step-by-step explanation:

Given that Jean bought a $ 1,980 snow thrower through an initial payment of 10% of the initial value, and 18 monthly payments of $ 116, to determine the final price paid by Jean, the following calculation is required:

(1,980 x 0.1) + (18 x 116) = X

198 + 2,088 = X

2,286 = X

Therefore, the final price paid for Jean was $ 2,286.

In turn, the finance charge arises from the difference between the final price and the list price, that is:

2,286 - 1,980 = X

306 = X

Thus, the finance charge is $ 306.

8 0

2 years ago

The sum of four consecutive odd integers is -72. Write an equation to model this situation, and ind the values of the four integ

Nutka1998 [239]

Answer:

equation: (x-3) +(x-1) +(x+1) +(x+3) = -72
values: -21, -19, -17, -15

Step-by-step explanation:

When dealing with consecutive integers, it often simplifies the problem to work with their average value. We know the average value of the integers in this problem is the even integer between the middle two. We can call it x, and write the equation ...

(x-3) +(x-1) +(x+1) +(x+3) = -72

This simplifies to ...

4x = -72 . . . . . . . we knew this before we wrote the above equation, since the sum of 4 numbers is 4 times their average.

x = -18 . . . . . . . . the middle number of the sequence

So, the numbers are:

-18-3 = -21
-18-1 = -19
-18+1 = -17
-18+3 = -15

_____

A more conventional approach is to define the variable as the integer at one end or the other of the sequence. If we make it be the lowest number, then the equation is ...

(x) +(x +2) +(x +4) +(x +6) = -72

and that simplifies to ...

4x +12 = -72 . . . . . collect terms

4x = -84 . . . . . . . . subtract 12

x = -21 . . . . . . . . . . divide by 4

Now, the other three numbers are found by adding 2, 4, and 6 to this one.

3 0

3 years ago

Use the Distance Formula to find the distance between D(2, 0) and E(8, 6).

Mazyrski [523]

Answer:

The answer is

<h2> $6 \sqrt{2} \: \: \: or \: \: \: 8.50 \: \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question

The points are D(2, 0) and E(8, 6

The distance between them is

$|DE| = \sqrt{ ({2 - 8})^{2} + ({0 - 6})^{2} } \\ = \sqrt{( { - 6})^{2} + ( { - 6})^{2} } \\ = \sqrt{36 + 36} \\ = \sqrt{72} \: \: \: \: \: \: \: \: \: \: \\ = 6 \sqrt{2} \: \: \: \: \: \: \: \: \: \: \\ = 8.4852813$

We have the final answer as

$6 \sqrt{2} \: \: \: or \: \: \: 8.50 \: \: \: \: units$

Hope this helps you

5 0

3 years ago