Answer:
<u>The number is 67</u>
Step-by-step explanation:
<u>Equations</u>
Let's consider the number 83. The tens digit is 8 and the unit digit is 3. Note the tens digit's addition to the number is 80, and the unit's addition is 3. This means the tens digit adds 10 times its value, that is, 83 = 8*10 + 3.
Now, let's consider the number ab, where a is the tens digit, and b is the unit digit. It follows that
Number=10*a+b
The question gives us two conditions:
1) The sum of a two-digits number is 13.
2) The tens digit is 8 less than twice the units digit.
The first condition can be expressed as:
a + b = 13 [1]
And the second condition can be written as:
a = 2b-8 [2]
Replacing [2] into [1], we have:
2b-8 + b = 13
Operating:
3b = 13 + 8
3b = 21
Solving for b:
b = 21 / 3 = 7
Substituting into [2]:
a = 2*(7) - 8 = 6
Thus, the number is 67
Answer: I'm pretty sure that it´s C but Im not sure.
Sorry if that's wrong.
Answer: 148
Work: 50 men multiplied by 3 =150
If there is two less women from 3 multiplied by 50 (150) , then 150 - 2 = 148
Answer:
70910 (c)
Step-by-step explanation:
You move the decimal point to the right each time.
we know that
If the point belongs to the graph, then the point must satisfy the equation
we will proceed to verify each case
<u>case A.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
not passes through the point 
<u>case B.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
passes through the point 
<u>case C.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
not passes through the point 
<u>case D.)</u> 
The point is 
Verify if the point satisfy the equation
For
find the value of y in the equation and compare with the y-coordinate of the point



therefore
the equation
passes through the point 
therefore
<u>the answer is</u>

