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vesna_86 [32]
2 years ago
8

How do we round 8.373 to the nearest hundredth?

Mathematics
1 answer:
Mashutka [201]2 years ago
3 0
8.373 rounded to the nearest hundredth is 8.37 because you look at the thousandths place or to the right of 7 and you see that its lower than 5 so you round down giving you the answer of 8.73

Answer: 8.73
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Suppose y = 2x + 1 , where x and y are functions of t. (a) if dx/dt = 6, find dy/dt when x = 4. dy dt = (b) if dy/dt = 2, find d
evablogger [386]

y=2x+1\\\\\dfrac{dy}{dt}=2\dfrac{dx}{dt}

(a) For dx/dt=6, dy/dt = 2·6 = 12

(b) For dy/dt=2, 2 = 2·dx/dt ⇒ dx/dt = 1

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The value of x is irrelevant for this question.

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Answer:

The rate at which water is being pumped into the tank is 13,913.27 cubic centimetre per minute

Step-by-step explanation:

Given that, the height of the conical tank is 13 meters and diameter is 3 meters.

Radius = \frac32 meters

\therefore \frac{radius }{height}=\frac {\frac{3}{2}}{13}

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V=\frac13 \pi (\frac3{26}h)^2 h

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Given that, the water level is rising at a rate of 17 cm per minute when the height 1 meter= 100 cm .i.e \frac{dh}{dt}=17 cm/min

Putting \frac{dh}{dt}=17  

\frac{dV}{dt}=\frac{9}{676}\pi h^2 \times 17

\frac{dV}{dt}|_{h=100}=\frac{9}{676}\pi (100)^2 \times 17

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The volume of water increases 7,113 cubic centimetre per minute while 6,800 cubic centimetre per minute is leaking out.

It means the required rate at which water is being pumped into the tank is

=(7,113+6,800)cubic centimetre per minute

=13,913 cubic centimetre per minute

           

   

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