we have
(a+b)(3a-b)(2a+7b)
step 1
Solve
apply distributive property
(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2
step 2
Multiply (3a^2-4ab-b^2) by (2a+7b)
6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3
answer is
<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
You can solve this by multiplying each numerator by the answer choices and trying to divide them. I can't get the fraction maker to work at the moment, so I'll write the calculations on a separate attachment.
As you can see, the only choice that works to eliminate both fractions is the fourth choice,
50x.
<h3>
Answer: 1/2 (choice A)</h3>
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Explanation:
The two equations given to us are
Divide the second equation over the first equation and that would lead to b = 6
Notice how the 'a' terms divide to 1 and go away, i.e. cancel out.
The b terms divide to (b^2)/b = b
The right hand side values divide to 18/3 = 6
So that's how we end up with b = 6
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Now if b = 6, then we can say,
ab = 3
a*6 = 3
a = 3/6
a = 1/2
Or we could say
ab^2 = 18
a*6^2 = 18
a*36 = 18
a = 18/36
a = 1/2
Step-by-step explanation:
Answer:
a and b are relative on maxima interval x =-4,x=0
