All categories

2 years ago

How do we round 8.373 to the nearest hundredth?

1 answer:

3 0

8.373 rounded to the nearest hundredth is 8.37 because you look at the thousandths place or to the right of 7 and you see that its lower than 5 so you round down giving you the answer of 8.73

Answer: 8.73

You might be interested in

What is an equation of the line that passes through the point (-5, -6) and is

Vikentia [17]

Answer: y= 2x +4

Step-by-step explanation:

1. To be able to write the equation of the line, you want to be able to find the slope first. To do so, rearrange the given equation x+2y=2 into slope-intercept form, which is y=mx+b

First subtract x from both side, which will give us 2y=2-x. Rearrange this to get 2y= -x+2. Then, divide both sides by 2. This will give us y= -1/2x+1

2. Now that you have the equation, look for the slope in the new equation; this will be the m value. In this case, the slope is -1/2. Since we are looking for a line that is perpendicular, we have to change the slope so that it is the opposite reciprocal. The opposite reciprocal of -1/2 is 2, so the slope of the equation we want to find is 2.

3. Next, all we have to do is plug the given ordered pair (-5, -6) and the slope that we found (m=2) into the point-slope equation, which is $y-y_{1} = m(x-x_{1} )$

That will give us:

y+6 = 2(x+5)

4. Now, solve this equation.

y+6 = 2(x+5) --> distribute the 2 inside the parentheses

y+6 = 2x + 10 --> subtract 6 from both sides

y= 2x +4

4 0

2 years ago

Patricia goes to shop at her favourite mall for a day. She spends $103, which is 62.4 percent of the total money that she brough

ASHA 777 [7]

Answer: 210.50$

Step-by-step explanation:

8 0

2 years ago

A rectangle has a height of 5y; and a width of 3y3 – 8y2 + 2y.

Korvikt [17]

Area= 15y^4-40y^3+10y^2

4 0

2 years ago

1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff

Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0

3 years ago

HELP PLEASE!!!!<br> what is the midpoint of (-5,-5) and (-1, -1)

Andreas93 [3]

(-3,-3) is your answer please give brainliest!

7 0

2 years ago

Read 2 more answers