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olga_2 [115]
2 years ago
6

.16 with the 6 repeating to a fraction

Mathematics
1 answer:
SVETLANKA909090 [29]2 years ago
5 0
The answer is


1/6









1/6
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The Frostburg-Truth bus travels on a straight road from Frostburg Mall to Sojourner Truth Park. The mall is 3 miles west and 2 m
Verizon [17]
To start, write your locations as points, with north and south being positive and negative y respectively and east and west being positive and negative x respectively. Doing this gives us the mall at (-3,-2) and the park at (4,5). Now, we use our distance formula ( \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 } ) to solve for the unknown distance. Plugging in with the park values as our second values and our mall values as our first values (as well as with our unknown distance as d), we get d= \sqrt{(4-(-3))^2+(5-(-2))^2} = \sqrt{(7)^2+(7)^2} = \sqrt{49+49} = \sqrt{98}. This square root can be rounded to 9.9 miles.
4 0
3 years ago
What is the answer to the math problem 5+9(2+4)?
IceJOKER [234]

Answer:

59

Step-by-step explanation:

Simplify the following:

5 + 9 (2 + 4)

2 + 4 = 6:

5 + 9×6

9×6 = 54:

5 + 54

5 + 54 = 59:

Answer:  59

6 0
2 years ago
Read 2 more answers
Help me with the part b!
ra1l [238]
Average speed =   (distance final - distance initial)/(time final - time initial)
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3/10 km/min *60 min/1 h = 180/10 km/h= 18 km/h
7 0
3 years ago
Triangle KJL is inscribed in semicircle O shown below such that JK=6 and JL=11. Which of the following is closest to the radius
lakkis [162]

Uhh, answer choices?

In any case, since \triangle KJL is inscribed in a semicircle, it is a right triangle (due to the inscribed angle theorem). Thus, by the Pythagorean theorem, KL=\sqrt{6^2+11^2}=\sqrt{157}. Now, the circumradius of a right triangle (the radius of the circle passing through all three of its vertices) is simply half its hypotenuse, so OJ=OK=OL=\frac{\sqrt{157}}{2}\approx \boxed{6.265}.

7 0
2 years ago
Completely factor 1-100x^2​
stiv31 [10]

Answer:

Since both terms are perfect squares, factor using the difference of squares formula,  a 2 − b2 = ( a + b ) (a − b )  where  a= 1  and  b = 10 x . ( 1 + 10 x ( 1 − 10 x )

Step-by-step explanation:

4 0
2 years ago
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