9.66
^ This is the tenths place.
Look at the number after it, if it's 5 or more we round up, if it's 4 or less we round down.
The number is 6, so we round up to 9.7.
<span>So we want to know how much ball bearings can be made with 5.24 cm^3 if one ball bearing has a diameter of 1 cm. We know that radius r=d/2=0.5cm So the volume V of one ball bearing is: V=(4/3)*pi*r^3 so V=(4/3)*3.14*(0.5)^3cm^3=0.524cm^3. Now we simply divide the volume of steel by the volume of the ball bearing: 5.24/0.524=10. So we can make 10 ball bearings from 5.24 cm^3 of steel</span>
Answer:
2n + 11
Step-by-step explanation:
You can combine 4n and -2n.
You get 2n + 11
Answer: 90
90 is a composite number because:
4 x 15 = 90
10 x 9 = 90
A composite number has more than two factors.
Hope this helps!
Answer:
x(85/100)
Step-by-step explanation:
100-15 = 85
x(85/100)