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3 years ago

Whose the best spiderman? A. Tobey B. Tobey Or C. Tobey?

Mathematics

2 answers:

Tanya [424]3 years ago

6 0

Answer:

tobey duh

Step-by-step explanation:

irinina [24]3 years ago

3 0

Tobey trust yes indeed

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For ten school days the numbers of bikes parked at a school bike rack are 10,12,8,11,13,9,2,1,9, and 12

kumpel [21]

Step-by-step explanation:

for this question is not even possible

6 0

3 years ago

Will a frying pan with a circumference of 25.12 inches fit on an electric burner with a 4-inch radius?

Leokris [45]

Answer:

Yes

Step-by-step explanation:

25.12 inches of circumference is equal to the radius of 3.998 inches

4 inches > 3.998 inches

Therefore it fits

8 0

3 years ago

Harmons and Smiths are having a sale on apples. Harmons charges $1.25 for 5 apples. Smiths charges $2.04 for 6 apples. Find the

8090 [49]

Answer:

0.09

Step-by-step explanation:

Divide 1.25 by 5 which is 0.25, and 2.04 by 6 which is 0.34

Then subtract the answers 0.34-0.25=0.09

7 0

3 years ago

Which expressions is equivalent to 2r+(t+r)

azamat

Answer:

t+3r

Step-by-step explanation:

This is a one step solution

All you do is add like terms

In this case the only like terms are the varibles r

2r+(t+r)

so if you add all of the rs together there would be 3rs

So the rest of the problem would continue as normal while bringing the 3r to the end

t+3r

8 0

3 years ago

Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

3 years ago