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Answer:
- Code is in JAVA language. As there is no user input the logic is straightforward.
- Below is the code along with a detailed explanation of the logic.
- The class name is Print main save as file as the main class.
Explanation:
Program:-
public class Main{
public static void main(String args[]){
/* There are two for loops...
* First for loop runs from i=1 to i=9
* Second for loop runs from j=1 to j=i.
*
*/
for(int i=1;i<=9;i++){
for(int j=1;j<=i;j++){ // j loop runs from j=1 to j=i
/*Prints I and j next to each other*/
System.out.println(i+""+j);
}//for loop of j ends here
}// for loop of I ends here
}
}
Answer:
1. row a horizontal set of data in a spreadsheet
2. spreadsheet software used by many business professionals to work with numbers
3. data information that is stored
4. template a file that serves as a starting point for a new document
5. function a built-in formula in a spreadsheet
6. invoice a statement you submit to get paid for a product or service
Explanation:
The correct matches have been mentioned in the answer section. Certainly, a row is the horizontal set of data is a spreadsheet. And other options are self-understood. And hence, it is self-explanatory.
Alternative 1:A small D-cache with a hit rate of 94% and a hit access time of 1 cycle (assume that no additional cycles on top of the baseline CPI are added to the execution on a cache hit in this case).Alternative 2: A larger D-cache with a hit rate of 98% and the hit access time of 2 cycles (assume that every memory instruction that hits into the cache adds one additional cycle on top of the baseline CPI). a)[10%] Estimate the CPI metric for both of these designs and determine which of these two designsprovides better performance. Explain your answers!CPI = # Cycles / # InsnLet X = # InsnCPI = # Cycles / XAlternative 1:# Cycles = 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150)CPI= 0.50*X*2 + 0.50*X(0.94*2 + 0.06*150) / X1= X(0.50*2 + 0.50(0.94*2 + 0.06*150) ) / X= 0.50*2 + 0.50(0.94*2 + 0.06*150)= 6.44Alternative 2:# Cycles = 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150)CPI= 0.50*X*2 + 0.50*X(0.98*(2+1) + 0.02*150) / X2= X(0.50*2 + 0.50(0.98*(2+1) + 0.02*150)) / X= 0.50*2 + 0.50(0.98*(2+1) + 0.02*150)= 3.97Alternative 2 has a lower CPI, therefore Alternative 2 provides better performance.
The ethernet address, a.k.a. mac address. That way, a DHCP server can give the same IP address to a returning client.
