Answer:
Start off with an interesting introduction (add questions) make it interesting.
Answer:
2 bytes
Explanation:
Size of the MAR ( memory address register ) = 18 bits = 2 bytes
Given that
address space = 256 K = 2^8
number of address location= 2^8 * 2^10 ( where 1K = 2^10 )
= 2^18
Given the number of address location = 2^18 ;
Hence 18 bits are required to store the address of the instruction
Answer:
D, document and explain parts of code
Explanation:
Mark me brainliest :)
Answer:
Ron is the answer
Explanation:
In that sense it is similar to secondary memory, which is used for long term storage. When a computer is turned on, the CPU can begin reading information stored in ROM without the need for drivers or other complex software to help it communicate.
Answer: data design model
Explanation:
