I dont' know im soooo sorry for not knowing
You can connect the point on the graph
x = 3 then y = 4
hope it helps
To find the x value of the max of
f(x)=ax^2+bx+c
when a is negative (if a is positive, we find the minimum)
we do
-b/2a is the x value
to find the y value, we just sub that x value back into the function
so
R(x)=-0.2x^2+60x+0
-b/2a=-60/(2*0.2)=-60/-0.4=150
x value is 150
make 150 units
sub back to find revenue
R(150)=-0.2(150)^2+60(150)
R(150)=-0.2(22500)+9000
R(150)=-4500+9000
R(150)=4500
max revenue is achieved when 150 units are produced yeilding $4500 in revenue
Answer:
Step-by-step explanation:
6 to the 16 power
Answer:
Step-by-step explanation:
To solve for the quotient, perform long division with the polynomials and write a remainder if necessary.
_x___-2_______
x - 1 | x2 + 0x - 4
x2 - 2x
_______________
-2x - 4
-2x + 2
_______________
-2
So the solution is
