3 years ago

Need help on this? Please help

Mathematics

1 answer:

Marysya12 [62]3 years ago

7 0

parallel: g(x) = -5/3x + 1

perpendicular: h(x) = 3/5x - 5

neither: j(x) = 2x + 3

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The sum of the series $\sum_{k=1}^{4}\left(2 k^{2}-4\right)$ is 44.

Step-by-step explanation:

The given series is $\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44$

To find the sum of the series, we need to substitute the values for k in the series.

$\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]$

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