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myrzilka [38]
3 years ago
10

5y + 10x = 0 y = - 3x Plz help me the photo is the directions for the problem

Mathematics
1 answer:
enyata [817]3 years ago
3 0
When substituting, you want to take the y value from one equation and plug it into the y variable in the other equation to find the x value. When you find the c value, you plug the number into one of the equations to get your y value.

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Please help I need an answer
Studentka2010 [4]

Answer:

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Step-by-step explanation:

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3 years ago
The line plot shos the number of hours students spend watching tv each night. Describe the data. Include measures of center vari
neonofarm [45]
I have no idea how about it lol lol yeah yeah
7 0
2 years ago
Anyone mind helping me solve this inequality? Step by step
dlinn [17]

By decomposing the figure in simpler shapes, we will see that the total area is:

a = 180 cm²

<h3>How to find the area of the composite figure?</h3>

Remember that the area of a rectangle of width W and length L is:

A = L*W

And the area of a triangle with base B and height H is:

A = B*H/2.

Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.

So the area of that part is:

A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²

Now, the bottom triangle has a base of 12 cm, and a height of:

15cm - 6cm = 9cm

Then its area is:

A' = 12cm*9cm/2 = 54cm²

This means that the total area of the figure is:

total area = 54cm² + 54cm² = 108cm²

If you want to learn more about area:

brainly.com/question/24487155

#SPJ1

5 0
2 years ago
Kim namjoon...<br><br> anyone army??
vova2212 [387]

Answer:

Er... um... huh?

Step-by-step explanation:

3 0
4 years ago
Read 2 more answers
What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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