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3 years ago

5y + 10x = 0 y = - 3x Plz help me the photo is the directions for the problem

Mathematics

1 answer:

enyata [817]3 years ago

3 0

When substituting, you want to take the y value from one equation and plug it into the y variable in the other equation to find the x value. When you find the c value, you plug the number into one of the equations to get your y value.

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Let x △ y be defined by x △ y=x−5y. What is the value of 3 △ (−4)

TEA [102]

$x\Delta y=x-5y\\\\3\Delta(-4)\qquad\text{put the values x = 3 and y = -4 to the expression x - 5y}:\\\\3\Delta(-4)=3-5(-4)=3+20=23$

5 0

3 years ago

How do I factor x^4-5x^2+6?

Vilka [71]

Answer:

$=(x^2-3)(x^2-2)$

Step-by-step explanation:

So we have the expression:

$x^4-5x^2+6$

And we wish to factor it.

First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

$=u^2-5u+6$

This is a technique called quadratic u-substitution. Now, we can factor in this form.

We can use the numbers -3 and -2. So:

$=u^2-2u-3u+6$

For the first two terms, factor out a u.

For the last two terms, factor out a -3. So:

$=u(u-2)-3(u-2)$

Grouping:

$=(u-3)(u-2)$

Now, substitute back the x² for u:

$=(x^2-3)(x^2-2)$

And this is the simplest form.

And we're done!

3 0

3 years ago

How many solutions does this equation have 10+5x/15=4

-Dominant- [34]

I think it only has One

8 0

3 years ago

Write an equation of a circle with a center at (2, - 4) and a radius of 4.

fgiga [73]

9514 1404 393

Answer:

(x -2)^2 +(y +4)^2 = 16

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

You have (h, k) = (2, -4) and r = 4, so your equation is ...

(x -2)^2 +(y -(-4))^2 = 4^2

(x -2)^2 +(y +4)^2 = 16

6 0

3 years ago

4x+15=6x-5 solve for x

hram777 [196]

Answer:

x = 10

Step-by-step explanation:

Breaking down the equation

$4x+15=6x-5\\4x+15-15=6x-5-15\\4x=6x-20\\4x-6x=6x-20-6x\\-2x=-20\\\frac{-2x}{-2}=\frac{-20}{-2}$

Simplification

$\frac{-2x}{-2}\\=\frac{2x}{2} (\frac{-x}{-y} = \frac{x}{y})\\\frac{2}{2} = 1 = x\\\\\frac{-20}{-2}\\=\frac{20}{2}\\\frac{20}{2}\\=10$

6 0

2 years ago

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