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zaharov [31]
3 years ago
11

Write an equation for the line that passes through E(4, -3) and is parallel to the line

Mathematics
1 answer:
olasank [31]3 years ago
3 0

Answer:

y= 5x/7 -27/7

if they are parallel there gradient is the same

m1=m2

y-y1=m(x-x1)

plug in the gradient and points E

y-(-3)=5/7( x-4)

y= 5/7(x) -20/7 +3

final answer

y= 5/7(x) +1/7

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Find the inverse of h(x)=(2x-4)/3
Agata [3.3K]

Answer:

The inverse of the h(x) is h^{-1}(x)=\frac{3x}{2}+2           Step-by-step explanation:

Given : Expression h(x)=\frac{2x-4}{3}

To find : The inverse of the expression ?

Solution :

Expression h(x)=\frac{2x-4}{3}

Let, h(x)=y then  y=\frac{2x-4}{3}

For inverse we replace the value of x and y and find the value of y in terms of x.

Replace the value of x and y,

x=\frac{2y-4}{3}

Solve for y by cross multiply,

3x=2y-4

Adding 4 both side,

3x+4=2y

Dividing by 2 both side,

\frac{3x+4}{2}=y

Therefore, The inverse of the h(x) is h^{-1}(x)=\frac{3x}{2}+2

5 0
3 years ago
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Collin did the work to see if 10 is a solution to the equation r/4=2.5
Natasha2012 [34]

Answer:

Yes, because if you substitute 10 for r in the equation and simplify, you find that the equation is true.

Step-by-step explanation:

\frac{r}{4}  = 2.5 \\ lhs =  \frac{r}{4}  \\  =  \frac{10}{4}  \\  = 2.5 \\  = rhs \\  \therefore \:  \frac{r}{4}  = 2.5 \\

3 0
3 years ago
Plz help becuase im trying to have this done in one min . ☝☝
In-s [12.5K]

Answer:

yes

Step-by-step explanation:

they both multiply by 20

4 0
3 years ago
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Use the distributive property to write an equivalent expression.
Tasya [4]

Answer:

32m + 24n

Step-by-step explanation:

Distribute the 8 to the other terms.

8(4m + 3n)

32m + 24n

6 0
3 years ago
Can anyone explain to me how to do this question ? ty !!​
julia-pushkina [17]

Step-by-step explanation:

use a little imagination.

the whole thing is a combination of churches and half- circles.

and you know the formula for the area of a circle ?

A = pi×r²

so, the only difficulty is to find the circles and then the radius of each involved circle.

when you look at the picture, the shaded area is almost identical to the lower half of the main circle.

2 bumps "look" over into the other side, but one equally sized bump is removed from this lower half.

so, as a first step we will calculate the area of the lower half of the main circle.

the diameter is 24 m, so the radius is half of that : 12m

the area of the large circle is therefore

pi×12² = 144×pi m²

since we only need the (lower) half, we divide this by 2 :

144×pi / 2 = 72×pi m²

the bumps up and down are actually half-circles too. just of smaller circles.

since AB = BC = CD, we know each of these lines are 1/3 of the main diameter AD.

so, the diameter of the smaller circles is 24/3 = 8 m

and their radius is half of that = 8/2 = 4m

the area of such a small circle is therefore

As = pi×4² = 16×pi m²

and a small half-circle area is then

16×pi / 2 = 8×pi m²

so, for the full shaded area I need to take the large half-circle and add 2 small half-circles, and then subtract 1 small half-circle.

so, in total I only need to add 1 small half-circle.

Ashaded = 72×pi + 8×pi = 80×pi m²

5 0
3 years ago
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