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Vikki [24]
3 years ago
7

A girl's feet are negative 4 over 6 yards from the surface of a pool. A boy's feet are negative 1 over 6 yards from the surface

of the pool. Determine whose feet are closer to the surface.
The girl's feet are closer to the surface of the pool because negative 4 over 6 > negative 1 over 6.
The boy's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.
The girl's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.
The boy's feet are closer to the surface of the pool because negative 4 over 6 > negative 1 over 6.
Mathematics
2 answers:
Flura [38]3 years ago
8 0

The boy's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.  

it will look like this: -4 over 6 < - 1 over 6.

GarryVolchara [31]3 years ago
8 0

<em>Answer:</em>

<em>B</em>

<h2><em><u>Step-by-step explanation:</u></em></h2><h2><em><u>The boy's feet are closer to the surface of the pool because negative 4 over 6 < negative 1 over 6.   </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>it will look like this: -4 over 6 < - 1 over 6.</u></em></h2>
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Answer:

Let the breadth is x, then the length is 3x.

<u>The area is:</u>

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<u>The breadth is decreased by 2 m: </u>

  • w = x - 2

<u>The length is increased by 4m: </u>

  • l = 3x + 4

<u>The area is now:</u>

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  • 3x² +  4x - 6x - 8 = 2x²
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The breadth was 4 m and the length  12 m

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14. BUS TRIP A bus leaves at 10 A.M. to take students on a field trip to a
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The bus is 54.5 miles far from the site at the time of 11:30A.M as per the given information in the question.

<h3>What is the slope of a line?</h3>

The slope of a line indicates how steep it is. Slope is defined mathematically as "climb over run" (change in y divided by change in x).

It is assumed that a bus moving at a constant speed departs at 10 a.m. towards a historic location, is 100 miles away by 10:25 a.m., and is 65 miles away at 11:15 a.m.

We must create a point-slope equation that connects the distance from the place to the time in minutes after 10:00 a.m. Then, around 11:30 a.m., we need to figure out how far the bus is from the site.

A line's point-slope is y₂-y₁)=m(x₂-x₁)

Since x denotes the amount of minutes after 10:00 a.m., 10:25 a.m. is represented by x=25 and 11:15 a.m. by x=75.

At 10:25 a.m., a distance of 100 miles from the place is represented by 75.

The point represents a distance of 100 miles from the site at 10:25 a.m. The point represents a distance of 65 miles from the site at 11:15 a.m.

By substituting the points (25, 100) and (75, 65) into the slope formula and simplifying we get,

m=(y₂-y₁)/(x₂-x₁)

m=(65-100)/(75-25)

m=-35/50

m=-0.7

Now choose one of the points and substitute that point and the slope into the slope-point form

y₋y₁=m(x-x₁)

By choosing (x₁, y₁)=(25, 100)

By choosing (x₂, y₂)=(75, 65)

Since 11:30 A,M is 90 minutes after 10:00A.M

By substituting x=90 in the equation we get the value of y,

y-100= -0.7(90-25)

y-100= -0.7(65)

y-100 =-45.5

y= 54.5

Hence, the bus is 54.5 miles from the site at the time of 11:30 A.M

y-100= -0.7(x-25)

OR

y-65= -0.7(x-75)

The bus is 54.5 miles from the site at 11:30A.M.

To know more about slope of a line, visit:

brainly.com/question/28771374

#SPJ9

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