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snow_lady [41]
3 years ago
15

How do you find the area of the shaded region

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

well, first off, let's notice that we have a trapezoid with a rectangle inside it, so the rectangle is really "using up" area that the trapezoid already has.

now, if we just get the area of the trapezoid, and then the area of the rectangle alone, and then subtract that area of the rectangle, the rectangle will in effect be making a hole inside the trapezoid's area, and what's leftover, is the shaded section, that part the hole is not touching.

\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h&=height\\ a,b&=\stackrel{parallel~sides}{bases} \\\cline{1-2} h&=8\\ a&=16\\ b&=8 \end{cases}\implies A=\cfrac{8(16+8)}{2}\implies A=96 \\\\\\ \stackrel{\textit{area of the rectangle}}{(5\cdot 3)\implies 15}~\hfill \stackrel{~\hfill \textit{shaded area}}{\stackrel{\textit{trapezoid}}{96}~~ - ~~\stackrel{\textit{rectangle}}{15}~~ = ~~81}

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grigory [225]

Slant height of tetrahedron is=6.53cm

Volume of the tetrahedron is=60.35\mathrm{cm}^{3}

Given:

Length of each edge a=8cm

To find:

Slant height and volume of the tetrahedron

<u>Step by Step Explanation: </u>

Solution;

Formula for calculating slant height is given as

Slant height=\sqrt{\frac{2}{3}} a

Where a= length of each edge

Slant height=\sqrt{\frac{2}{3}} \times 8

                     =\sqrt{0.6667} \times 8

                     =0.8165 \times 8=6.53cm

Similarly formula used for calculating volume is given as

Volume of the tetrahedron=\frac{a^{3}}{6 \sqrt{2}}

Substitute the value of a in above equation we get

Volume=\frac{8^{5}}{6 \sqrt{2}}

            =\frac{512}{6 \sqrt{2}}

            =\frac{512}{6 \times 1.414}

Volume=512 / 8.484=60.35\mathrm{cm}^{3}

Result:

Thus the slant height and volume of tetrahedron are 6.53cm and 60.35\mathrm{cm}^{3}

7 0
2 years ago
Find k so that the following function is continuous:<br> f(x)={kx8x2if0≤x&lt;5if5≤x.
tankabanditka [31]

Check the one-sided limits:

\displaystyle \lim_{x\to5^-}f(x) = \lim_{x\to5}kx = 5k

\displaystyle \lim_{x\to5^+}f(x) = \lim_{x\to5}8x^2 = 200

If <em>f(x)</em> is to be continuous at <em>x</em> = 5, then these two limits should have the same value, which means

5<em>k</em> = 200

<em>k</em> = 200/5

<em>k</em> = 40

3 0
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Bogdan [553]

Answer:

C. xy²

Step-by-step explanation:

You have to add the exponents:

(xy) exponent is 1

(x) exponent is 1

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xy²

5 0
2 years ago
1
saul85 [17]

Answer:

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8 0
3 years ago
Solve for x: x/-6 = -7
vladimir1956 [14]

Answer: X=42

Step-by-step explanation:

42/-6=-7

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3 0
2 years ago
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