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2 years ago

Given the graph of the polynomial function

Mathematics

1 answer:

jarptica [38.1K]2 years ago

3 0

Step-by-step explanation:

according to the graph, the correct answer is:

possitive : (-1, 2) and (6, oo)

negative : (-oo, -1) and (2, 6)

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What is the following sum? 5(3√x)+9(3√x)

charle [14.2K]

5(3√x)+9(3√x)
=3√x(5+9)
=14(3√x)

answer is C. third choice 14(3√x)

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2 years ago

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How would you write 62.22 in expanded form

BARSIC [14]

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3 years ago

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(b) The perimeter of a rectangular painting is 250 cm.

hodyreva [135]

53x2=106
250-106= 144
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2 years ago

7800 nm + 95 pm in scientific notation

azamat

$7800 nm+95pm=7800* 10^{-9} +95* 10^{-12}$
$=7800000* x^{-12} +95* 10^{-12} =7800095* 10^{-12} =7.800095* 10^{-6}$

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2 years ago

. Given that O is the centre of the following circle, find the values of the unknowns.

alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

$a^{2} + 5^{2} = 13^{2}$

$a^{2} + 25 = 169$

$a^{2} = 169 - 25$

$a^{2} = 144$

$\sqrt{a^{2}}=\sqrt{144}$

$a = 12$

Now to find the value of 'b', i will use law of cosine,

$c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }$

$12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta = 0.3846\\\beta = cos^{-1}(0.3846)\\\beta = 67.38$

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

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2 years ago