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aksik [14]
3 years ago
15

Does 5.2 belong with irrational or rational numbers?

Mathematics
1 answer:
Dominik [7]3 years ago
7 0

Answer:

The correct answer is "rational" . It is not an "integer" because it is a "decimal value". It is not "irrational" because the decimal value terminates and does not repeat.

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In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.
zvonat [6]

Part i


\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}


y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}


Substituting,

y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1


Answer: -1


Part ii


I'm not sure that one's typed in correctly but I'll solve it as written.


3-34y + 2a = \dfrac{3b-5}{2c + 1}


34y  = 3+2a-\dfrac{3b-5}{2c + 1}


y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)


We're not asked to simplify it so I wont. Substituting,


y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}


Answer: 59/306



3 0
3 years ago
?????????????? anyone
Keith_Richards [23]

Answer:

(6 + 3/n) -8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
R 2x-6+3=6x-5 please help
frozen [14]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

2x - 6 + 3 = 6x - 5

2x - 3 = 6x - 5

6x - 5 = 2x - 3

Add sides 5

6x - 5 + 5 = 2x - 3 + 5

6x = 2x + 2

Subtract sides 2x

- 2x + 6x =  - 2x + 2x + 2

4x = 2

Divide sides by 4

\frac{4x}{4}  =  \frac{2}{4}  \\

x =  \frac{1}{2}  \\

_________________________________

CHECK :

2( \frac{1}{2} ) - 3 = 6( \frac{1}{2} ) - 5 \\

1 - 3 = 3 - 5

- 2 =  - 2

Thus the solution is correct....

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

3 0
3 years ago
Read 2 more answers
Four statements are given below.
goldfiish [28.3K]

Answer:

I and III

Step-by-step explanation:

mark me as brainliest

4 0
3 years ago
What's the measure of m∠JKL?
AleksandrR [38]

Answer:

sorry, I think yr question is incomplete.

3 0
3 years ago
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