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enyata [817]
3 years ago
12

A roadside vegetable stand sells pumpkins for $5 each and tomatoes for $3 each. The

Mathematics
1 answer:
stealth61 [152]3 years ago
3 0

Answer:

Step-by-step explanation: I need help

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The HA Theorem is a special case of the AAS postulate.
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A company is constructing an​ open-top, square-based, rectangular metal tank that will have a volume of 49 cubic feet. What dime
yawa3891 [41]

Answer:

b = 4.6 ft

h = 2.3 ft

Step-by-step explanation:

The volume of the tank is given by:

b^2*h=49

Where 'b' is the length of the each side of the square base, and 'h' is the height of the tank.

The surface area can be written as:

A=b^2+4bh\\A=b^2+4b*({\frac{49}{b^2}})\\A=b^2+\frac{196}{b}

The value of b for which the derivate of the expression above is zero is the value that yields the minimum surface area:

\frac{dA}{db} =0=2b-\frac{196}{b^2}\\2b^3=196\\b=4.61\ ft

The value of h is then:

h=\frac{49}{4.61^2}\\h=2.31\ ft

Rounded to the nearest tenth, the dimensions are b = 4.6 ft and h = 2.3 ft.

7 0
3 years ago
Felix was asked whether the following equation is an identity:<br> (x^2-1)^2=(x^2-1)+(2x)^2
Rudiy27

Answer:

The answer is no

Step-by-step explanation:

The equation is not an identity

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Find the area an perimeter
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Answer:

Perimiter :: 24

Area :: 28

6 0
3 years ago
Given cscx/cotx=sqrt2, find a numerical value of one trigonometric function of x.
Firlakuza [10]

   \frac{csc (x)}{cot (x)} = \sqrt{2}

⇒ \frac{csc (x)}{1} * \frac{1}{cot (x)} = \sqrt{2}

⇒ \frac{1}{sin (x)} * \frac{sin(x)}{cos (x)} = \sqrt{2}

⇒\frac{1}{cos (x)} = \sqrt{2} ; sin(x) ≠ 0, cos(x) ≠ 0

⇒ \frac{cos (x)}{1} = \frac{1}{\sqrt{2}}; sin(x) ≠ 0, cos(x) ≠ 0

⇒ cos (x) = \frac{\sqrt{2}}{2}

Use the Unit Circle to determine when cos (x) = \frac{\sqrt{2}}{2}

Answer: 45° and 315°  (\frac{\pi}{4} and \frac{7\pi }{4} )


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3 years ago
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