Answer:
175°
Step-by-step explanation:
Bearing angles are usually measured clockwise from North. Reverse bearing angles differ from forward bearing angles by 180°. These relations and the usual angle sum relation for a triangle can be used to solve this problem.
Angle PQR will be the difference in the bearings from Q to P and Q to R:
∠PQR = 124° -46° = 78°
Triangle PQR is isosceles, so the base angle at P will be ...
∠QPR = (180° -78°)/2 = 51°
__
The bearing from P to R will be 51° less than the bearing from P to Q. The bearing from P to Q is 180° more than the bearing from Q to P.
PR bearing = PQ bearing - ∠QPR
= PQ bearing - 51°
= (46° +180°) -51° = 175°
The bearing of R from P is 175°.
Answer:
13- No because the size of the triangle can be different, meaning bigger side length
in 14 he is forgetting the lines at the angles. The little circular ones that say the angles are congruent.
Step-by-step explanation:
Answer:
4s¹²/(9t⁴)
Step-by-step explanation:
<u>Solving in steps:</u>
- (3s⁻⁴t⁷s⁰)⁻²(-2s²t⁵)² =
- 3⁻²s⁻⁴ˣ⁻²t⁷ˣ⁻²(-2)²s²ˣ²t⁵ˣ² =
- 1/9×s⁸t⁻¹⁴(4)s⁴t¹⁰ =
- 4/9 ×s⁸⁺⁴t⁻¹⁴⁺¹⁰ =
- 4/9 ×s¹²t⁻⁴=
- 4s¹²/(9t⁴)
Answer:
Slope:
3
/5
y-intercept:
−
6
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
Consider the sequence 10, 6, 2, -2, -4, ...
Rewrite it as
The points on the coordinate plane are
(see attached graph).
Since
given sequence is arithmetic.
