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ivolga24 [154]
3 years ago
8

SIMPLIFY THE FOLLOWING EXPRESSION: given that s ≠ 0, and write your answer using only positive exponents. Thanks in advance!!!

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

4s¹²/(9t⁴)

Step-by-step explanation:

<u>Solving in steps:</u>

  • (3s⁻⁴t⁷s⁰)⁻²(-2s²t⁵)² =
  • 3⁻²s⁻⁴ˣ⁻²t⁷ˣ⁻²(-2)²s²ˣ²t⁵ˣ² =
  • 1/9×s⁸t⁻¹⁴(4)s⁴t¹⁰ =
  • 4/9 ×s⁸⁺⁴t⁻¹⁴⁺¹⁰ =
  • 4/9 ×s¹²t⁻⁴=
  • 4s¹²/(9t⁴)
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Veronika [31]

Answer

about 4 hours and 20 minutes

Step-by-step explanation:

200 divided by 60 is 3.33 or 3 hours and 20 minutes, plus the extra hour

8 0
3 years ago
Solve for B.<br> Ax+By=C<br> What is B equal to?<br> B=C−Ax/y<br> B=C/Axy<br> B=C/Ax −y<br> B=C−Ax−y
AfilCa [17]

Answer:

B = (C-Ax)/y

Step-by-step explanation:

Solve for B.

Ax+By=C

making B the subject of formula '

Ax+By=C

subtract Ax from both sides

By = C-Ax

By = C-Ax

divide both sides by y

B = (C-Ax)/y

4 0
3 years ago
Read 2 more answers
There are 53 regular pencils in the box and some colored pencils in the box. There are a total of 84 pencils. How many colored p
vodka [1.7K]

Let be "x" the number of colored pencils in the box.

According to the information given in the exercise, there are 84 pencils in the box and 53 of them are regular pencils.

Knowing this information, you can set up the following equation:

x+53=84

Finally, you have to solve for the variable "x" in order to find its value. In order to do this, you can apply the Subtraction property of equality by subtracting 53 from both sides of the equation:

\begin{gathered} x+53-(53)=84-(53) \\ x=31 \end{gathered}

The answer is: There are 31 colored pencils in the box.

7 0
1 year ago
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
2 years ago
What is the solution to the equation below? riund your answer to two decimal places. (24) log(3x) = 60
Amanda [17]

The answer is:  " x = 105.41 " . 

_____________________________________________

Explanation:

_____________________________________________

Given:   " 24 log (3x) = 60 " ;  Solve for "x" .

The default is to assume "base 10" for the "logarithm". 

_____________________________________________

Start by dividing each side of the equation by "24" ; 

       →   [ 24 log(3x) ] / 24  = 60 / 24 ; 

to get:  

_____________________________________________

 log (3x)  = 2.5 ;

_____________________________________________

Rewrite as:  log₁₀ (3x) = 2.5 ;  

_____________________________________________

Using the property of logarithms:

⇔    10⁽²·⁵⁾  =   3x  ;  

↔   3x = 10⁽²·⁵⁾   ;

         →  10^ (2.5) = 316.2277660168379332 ;

     →  3x = 316.227766016837933 ;  

Divide each side of the equation by "3" ;

  to isolate "x" on one side of the equation;

      and to solve for "x" ;

    →  3x / 3 =  316.2277660168379332 / 3  ;

to get:

    →   x = 105.4092553389459777333 ;

    →  round to 2 (two) decimal places;

_____________________________________________

         →   " x = 105.41 " .

_____________________________________________

 Hope this helps!

    Best wishes to you!

_____________________________________________

8 0
2 years ago
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