Answer:
y = 1/2x + 4
Step-by-step explanation:
If it's parallel, then the slope will remain the same.
To find the y-intercept, you have to plug the coordinates into the equation.
y = 1/2x + b
6 = 1/2 (4) + b
6 = 2 + b
4 = b
Given:$7/child
$10/adult
Total people = 700
Total money = $6,400
First, make two equations.
Let a = # of adults & Let c = # of children.
Let p = total people
1. a+c = 700
2. 10a+7c = 6,400
Then, rearrange the equation to solve for a variable.
c = 700-a
Substitute (700-a) for c, or the # of children in the second equation.
10a+(700-a) = 6400
9a+700 = 6400
9a+700-700 = 6400-700
9a = 5700
9a/9 = 5700/9
a = 633 = # of adults attended700-633
= c =
66 = # of children attended
Answer:69
Step-by-step explanation:
A) $16
B) p(x) = 16x -800
C) 69 ticketsn:
A) The total of expenses is ...
$280 +100 +20 +400 = $800
If this is covered by 50 tickets, then a ticket must provide revenue of ...
$800/50 = $16
The cost per ticket is $16.
__
B) The profit is the difference between revenue and expenses. The revenue from sale of x tickets will be 16x. The expenses are fixed at 800, so the profit is ...
p(x) = 16x -800
__
C) We can find the number of tickets to sell (x) in order for profit to be at least $300 by solving the inequality ...
p(x) ≥ 300
16x -800 ≥ 300 . . . . . use the expression for p(x)
16x ≥ 1100 . . . . . . . . . add 800
x ≥ 68.75 . . . . . . . . . . divide by 16 . . . (the least satisfactory integer is 69)
In order to raise at least $300, the number of tickets sold must be at least 69.
People will need to go through more than one obstacle at three places in the course: The 1/3 mark, the 1/2 mark, and the 2/3 mark.
The tires are at these spots
--\--\--\--\--\--\
The cones are at these spots
----\----\----\
And the hurdles are here:
------\------\
When you combine these:
--\--\\--\\--\\--\--\\\
You get two marks at the 1/3, 1/2, 2/3, and Final spots (Final can be 1, 2/2, 3/3, or 6/6.)