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2 years ago

L will give Brainliest...Anyone

Mathematics

1 answer:

BaLLatris [955]2 years ago

7 0

Answer and Step-by-step explanation:

We first need to solve for x, and by doing that, we would need to multiply the length and width of the shaded box, have it be subtracted by the area of the inside box, and then equal it to the area.

(6x * x) -[(x + 4)(x - 1)] = 40.

$6x^2 - x^2 -3x + 4 = 40\\\\Simplify\\5x^2 - 3x + 4 = 40\\\\$

Subtract 40 from both sides of the equation.

$5x^2 - 3x - 36 = 0$

Now, factor the equation.

$(5x+12)(x-3)\\$

Solve for x.

x = $\frac{-12}{5}$

x = 3

If we were to plug in $\frac{-12}{5}$ for the width of the flower bed rectangle, we would get a negative side value, which we know isn't possible.

So, x is equal to 3.

Now, we plug 3 in for the x values.

3 + 4 = 7

3 - 1 = 2

Finally, we multiply the sides to get the area.

7 * 2 = 14.

The area of the flowerbed is 14 $m^2$ .

#teamtrees #PAW (Plant And Water)

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The cost of 5kg of rice is Rs.425. find the cost of 1kg of rice

DaniilM [7]

Answer:

Rs 85

Step-by-step explanation:

Cost of 5kgs of rice = Rs 425

Cost of 1 kg of rice = 425/5

= Rs 85

So, the cost of a kg of rice is Rs 85

8 0

2 years ago

A 51-foot wire running from the top of a tent pole to the ground makes an angle of 58° with the ground. If the length of the ten

AfilCa [17]

Answer:

35.11 ft

Step-by-step explanation:

This given situation can be thought of as triangle $\triangle PQR$ where PQ is the length of pole.

PR is the length of rope.

and QR is the distance of bottom of pole to the point of fastening of rope to the ground.

And $\angle Q \neq 90^\circ$

Given that:

PQ = 44 ft

PR = 51 ft

$\angle R = 58^\circ$

To find:

Side QR = ?

Solution:

We can apply Sine Rule here to find the unknown side.

Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\dfrac{PR}{sinQ}=\dfrac{PQ}{sinR}\\\Rightarrow sin Q =\dfrac{PR}{PQ}\times sinR\\\Rightarrow sin Q =\dfrac{51}{44}\times sin58^\circ\\\Rightarrow \angle Q =79.41^\circ$

Now,

$\angle P +\angle Q +\angle R =180^\circ\\\Rightarrow \angle P +58^\circ+79.41^\circ=180^\circ\\\Rightarrow \angle P = 42.59^\circ$

Let us use the Sine rule again:

$\dfrac{QR}{sinP}=\dfrac{PQ}{sinR}\\\Rightarrow QR =\dfrac{sinP}{sinR}\times PQ\\\Rightarrow QR =\dfrac{sin42.59}{sin58}\times 44\\\Rightarrow QR = 35.11\ ft$

So, the answer is 35.11 ft.

3 0

3 years ago

if 3/5 of the wall is made from brick how do you determine the height of the brick portion of the wall

photoshop1234 [79]

Try dividing the surface area of the wall by 6.

6 0

3 years ago

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Savatey [412]

we have that

$300 + 150 + 75 +...$

Let

$a1=300\\ a2=150\\ a3=75$

we know that

$\frac{a2}{a1} =\frac{150}{300} \\\\ \frac{a2}{a1}=0.5 \\ \\ a2=a1*0.50$

$\frac{a3}{a2} =\frac{75}{150} \\\\ \frac{a3}{a2}=0.5 \\ \\ a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\\ S5=300+150+75+37.5+18.75\\ S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=\frac{a_1 (1-r^n)}{1-r} \\\\a_1=300 \\ r=\frac{1}{2}\\\\ S_5=\frac{300(1-(\frac{1}{2})^5)}{1-\frac{1}{2}}\\\\=\frac{300(1-\frac{1}{32})}{\frac{1}{2}}\\\\=\frac{300 \times \frac{31}{32}}{\frac{1}{2}}\\\\=\frac{75 \times \frac{31}{8}}{\frac{1}{2}}\\\\=\frac{\frac{2325}{8}}{\frac{1}{2}}\\\\=\frac{2325}{8} \times 2\\\\=\frac{2325}{4}\\\\=581 \frac{1}{4}\\\\=581.25$