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2 years ago

Please help thanks so much

Mathematics

1 answer:

GalinKa [24]2 years ago

8 0

The answer is c using substitution :)

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3 years ago

X= 7 4. Find the equation of a line passing through (5, -6) perpendicular (b) 3x + 5y = (d) 7x - 12y (f) x = 7 (a) 2x + y = 12 (

goldfiish [28.3K]

Given data:

The first set of equations are x+y=4, and x=6.

The second set of equations are 3x-y=12 and y=-6.

The point of intersection of first set of te equations is,

6+y=4

y=-2

The first point is (6, -2).

The point of intersection of second set of te equations is,

3x-(-6)=12

3x+6=12

3x=6

x=2

The second point is (2, -6).

The equation of the line passing through (6, -2) and (2, -6) is,

$\begin{gathered} y-(-2)=\frac{-6-(-2)}{2-6}(x-6) \\ y+2=\frac{-6+2}{-4}(x-6) \\ y+2=x-6 \\ y=x-8 \end{gathered}$

Thus, the required equation of the line is y=x-8.

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1 year ago

Pls help photo included !!!!

AlladinOne [14]

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3 years ago