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kiruha [24]
2 years ago
13

Draw a number line diagram and write an expression to represent this situation: “On Tuesday at lunchtime, it was 29° C. By sunse

t, the temperature had dropped to 16° C.
Mathematics
2 answers:
777dan777 [17]2 years ago
8 0

Answer:

Step-by-step explanation:

but the answer is the temperature dropped 15.6 degrees from the high that day which was 8 degrees

so the sum is: 8-15.6= -7.6

And that means the low temperature on Tuesday night was - 7.6 degrees

Step-by-step explanation:

xkjs

Anvisha [2.4K]2 years ago
3 0

Answer:

not you cheating Maddison   (its kaliya)

Step-by-step explanation:

but the answer is the temperature dropped 15.6 degrees from the high that day which was 8 degrees

so the sum is: 8-15.6= -7.6

And that means the low temperature on Tuesday night was - 7.6 degrees

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In the coordinates of A are (-2,3) and the coordinates of B are (7,-1), find the length of AB
nekit [7.7K]

Answer:

√97

Step-by-step explanation:

5 0
3 years ago
En la fábrica de Don Toño hoy fabricaron 320 pantalones, si los guardan en cajas donde caben 50 ¿cuántas cajas llenaron?
Scrat [10]

Answer:

6.4 Cajas

Step-by-step explanation:

320/50 = 6.4 Cajas

8 0
3 years ago
Consider the parabola y = 5x − x2. (a) find the slope m of the tangent line to the parabola at the point (1, 4).
kkurt [141]
The tangent line to a curve is the one that coincides with the curve at a point and with the same derivative, that is, the same degree of variation.
 We have then:
 y = 5x-x²
 Deriving:
 y '= 5-2x
 In point (1, 4)
 The slope is:
 y (1) '= 5-2 * (1)
 y (1) '= 3
 The equation of the line will be:
 y-f (a) = f '(a) (x-a)
 We have then:
 y-4 = 3 (x-1)
 Rewriting:
 y = 3x-3 + 4
 y = 3x + 1
 Answer:
 the tangent line to the parabola at the point (1, 4) is
 y = 3x + 1
 the slope m is
 m = 3
7 0
3 years ago
Solve 9x + 3 = -33 . PLEASE HELP ME IT WILL MAKE MY DAY​
ValentinkaMS [17]

:  \implies \sf 9x + 3 =  - 33

: \implies \sf 9x =  - 33 - 3

:  \implies \sf 9x =  - 36

:  \implies \sf x =  \dfrac{ - 36}{9}  =  - 4

\therefore  \sf x =  -4

8 0
3 years ago
Read 2 more answers
Given the equation 4x2 − 8x 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 k = 0?
Westkost [7]

The vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

According to the given question.

We have a quadratic equation

4x^{2} -8x + 20 = 0

Since, for the standard quadratic form is ax^{2} +bx + c = y, the vertex form of a quadratic equation is y = a(x -h)^{2} + k where (h, k) is the vertex.    

And h and k can be calculated as

h = -b/2a and y = k

So, for the given equation 4x^{2} -8x + 20 =0 the vertex (h, k) is given by

h = -(-8)/2(4) = 8/8 = 1   (X coordinate of vertex)

and,

y =4x^{2} -8x+ 20

substitute x = 1 in the above equation for the value of k

Y = 4(1)(1) - 8(1) + 20

⇒ Y = 4 - 8 + 20

⇒ Y = -4 + 20

⇒ Y = 16

so, k = 16          (Y coordinate of vertex)

Now, substitute the value of a, k and h in y = a(x-h)^{2} + k.

⇒  0 =4(x-1)^{2} + 16

Therefore, the vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

Find out more information about vertex form of a quadratic equation here:

brainly.com/question/12223454

#SPJ4

6 0
1 year ago
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