The values of the given trig functions in terms of sinθ and/or cosθ are:
sinθ = <u>tanθ.cosθ</u>
cosθ = <u>sinθ/tanθ</u>
secθ = <u>1/cosθ</u>
cscθ = <u>1/sinθ</u>
tanθ = <u>sinθ/cosθ</u>
cotθ = <u>cosθ/sinθ</u>
<h3>Trigonometric functions </h3>
From the question, we are to determine the values of the given trig functions in terms of sinθ and/or cosθ
NOTE: tanθ = sinθ / cosθ
∴ sinθ = tanθ.cosθ
From above, we can write that
cosθ = sinθ/tanθ
Secant is the <u>inverse</u> of cosine
∴ secθ = 1/cosθ
Cosecant is the <u>inverse</u> of sine
∴ cscθ = 1/sinθ
tanθ = sinθ/cosθ
Cotangent is the <u>inverse</u> of tangent
∴ cotθ = 1/tanθ
But, tanθ = sinθ/cosθ
∴ cotθ = cosθ/sinθ
Hence, the values of the given trig functions in terms of sinθ and/or cosθ are:
sinθ = <u>tanθ.cosθ</u>
cosθ = <u>sinθ/tanθ</u>
secθ = <u>1/cosθ</u>
cscθ = <u>1/sinθ</u>
tanθ = <u>sinθ/cosθ</u>
cotθ = <u>cosθ/sinθ</u>
Learn more on Trigonometric functions here: brainly.com/question/10316891
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You are going to have 9 apples
Answer:
C
Step-by-step explanation:
Answer: A) stretched vertically by 2 and shifted up 6 units
<u>Step-by-step explanation:</u>
y = A log(Bx - C) + D where
- A = vertical stretch by a factor of A
- B = horizontal shrink by a factor of 1/B
- C = horizontal shift C units (positive = right, negative = left)
- D = vertical shift D units (positive = up, negative = down)
Given: f(x) = log x
g(x) = 2 log x + 6
→ A = 2 vertical stretch by a factor of 2
→ D = +6 vertical shift UP 6 units