3 years ago

Solve the equation 2 16x + 20 = 0 to the nearest tenth.

Mathematics

2 answers:

Mazyrski [523]3 years ago

5 0

Answer:

x=(-1.25)

Step-by-step explanation:

16x+20=0

Subtract 20 from both sides

16x=(-20)

Divide 16 on both sides

x=(-1.25)

-1.25*16+20=0

-20+20=0

0=0

Alenkasestr [34]3 years ago

3 0

Answer:

x ≈ - 1.3

Step-by-step explanation:

16x + 20 = 0

16x + 20 - 20 = 0 - 20

16x = - 20

16x ÷ 16 = - 20 ÷ 16

x = - 1.25

$x=-1\frac{1}{4}$

- 1.25 rounds to - 1.3

You might be interested in

Fred has a bag containing 12 black marbles, 10 red marbles, and 15 white marbles .

-Dominant- [34]

Answer:

I dont understand your question but I'm going to assume that you want to add those numbers the answer would be 37 marbles in total

7 0

3 years ago

I need your help guys help me differentiate this question

Elden [556K]

Answer:

$6((4 {x}^{3} - 5x + 1) ^{ - 4} + 4 {x}^{10} + 4) ^{5} \times (- 4(4x ^{3} - 5x + 1)^{ - 5} \times 12 {x}^{2} - 5 ) + 40 {x}^{9}$

3 0

2 years ago

I need help finding the answers for all of these, I've been stuck on it for the last 30 minutes

Vinvika [58]

Answer:

Ray: A

Vertex:AC

Angle:ABX

Parallel lines:CFB FCB BCF

Parallel planes:BCC

Coplanar points:A F

Colliner points:C D E F

Segment addition postulate:ANB

Prependicular:????

7 0

2 years ago

What set of numbers does ^22 fall between

Licemer1 [7]

Answer:

4 and 5

Step-by-step explanation:

If you mean what $\sqrt{22}$ falls into, you would get something in between 4 and 5.

We can solve this by first finding a square root that is higher than that, which is $\sqrt{25}$ and $\sqrt{16}$ .

If we go by that $\sqrt{22}$ falls in between 4² and 5².

Cheers!

5 0

2 years ago

Help pls

rjkz [21]

Answer:

b they are both solution

8 0

3 years ago

Read 2 more answers