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worty [1.4K]
3 years ago
10

There is a closed carton of eggs in Mai's refrigerator. The carton contains e eggs and it can hold 12 eggs. What are some possib

le values of e that will make both e<12 and e>0 true?
Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

1,2,3,4,5,6,7,8,9,10,11

Step-by-step explanation:

plato

nevsk [136]3 years ago
3 0

Answer:

e<12 the value of e can be written as 0<12 and e>0 the value of e in this can be 12>0

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Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How m
8_murik_8 [283]

Value of the given statement:

  1. 4.36
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  3. 6
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<h3>What is Probability?</h3>

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a claim to be true. A number between 0 and 1 is the probability of an event, where, broadly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

According to the given information:

1) There are a total of 10 slips after adding.

8 slip with 3 on it

2 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 11)  x 3 + (2/ 11)  x 9

24 / 11 + 24 / 11 = 4.36

2 )No of total slips after addition = 12

8 slip with 3 on it

4 slips with 9  on it

 value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 12)  x 3 + (4 / 12)  x 9

2 + 3 = 5

3 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

value = Probability of 3 x 3 plus Probability of 9 x 9.

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 6

24 + 18 + 9n / 10 + n  = 6

42 + 9n = 60 + 6n

3 n = 18

n = 6

4 )Let n be the required number

No of total slips after addition = 10+n

8 slip with 3 on it

2 + n  slips with 9  on it

expectation value = probability of 3 x 3 + probability of 9 x 9

=  (8 / 10+n )  x 3 + (2+n  / 10+n )  x 9 = 8

24 + 18 + 9n / 10 + n  = 8

42 + 9n = 80 + 8n

n = 38

Minimum of 38 has to be added .

To know more about Probability visit:

brainly.com/question/17487084

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I understand that the question you are looking for is:

1:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add one additional $9$ to the bag? 2:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. What is the expected value of the number shown if we add two additional $9$'s (instead of just one) to the bag? 3:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do we have to add to make the expected value equal to $6$? 4:Suppose we have a bag with $10$ slips of paper in it. Eight slips have a $3$ on them and the other two have a $9$ on them. How many $9$'s do I have to add before the expected value is at least $8$?

4 0
2 years ago
Can yall help me please?
eduard

Answer:

5/6 - 2/5 = 13/30

Step-by-step explanation:

6 0
3 years ago
[Function Composition] could someone help me with this answers or show work either is fine
zavuch27 [327]

Answer:

21

Step-by-step explanation:

Given the following expressions

f(x) = x³-2x

g(x) =-x-2

We are to find (fog)(-5)

fog = f(g(x))

f(g(x)) = f(-x-2)

Replace x with -x-2 in f(x)

f(-x-2) = (-x-2)³-2(-x-2)

f(-x-2) = (-x-2)³+2x+4

fog = (-x-2)³+2x+4

Substitute x = -5 into the result

fog(-5) = (-x-2)³+2x+4

fog(-5) = (-(-5)-2)³+2(-5)+4

fog(-5) = (5-2)³-10+4

fog(-5) = 3³-6

fog(-5) = 27-6

fog(-5) = 21

Hence the required result of the composite function is 21

8 0
3 years ago
Can the mean (average) be greater than the largest number in a data set?
salantis [7]
No it can never be greater than the largest number in the set because an average (or a mean) is the "<span> number expressing the central or typical value in a set of data, in particular the mode, median, or (most commonly) the mean, which is calculated by dividing the sum of the values in the set by their number." c:</span>
3 0
3 years ago
The rectangle below has an area of 8x^5+12x^3+20x^28x 5 +12x 3 +20x 2 8, x, start superscript, 5, end superscript, plus, 12, x,
juin [17]

Answer:

The width is: w(x)=4x^2

The length is l(x)=2x^2+3x+5

Step-by-step explanation:

The given rectangle has area given algebraically by the function:

a(x)=8x^5+12x^3+20x^2

The width of the rectangle is the greatest common factor of 8x^5,  12x^3 and 20x^2

That is the width is: w(x)=4x^2

We now divide the area by the width to obtain the length of the rectangle:

l(x)=\frac{8x^5+12x^3+20x^2}{4x^2}

This simplifies to:

l(x)=\frac{8x^5}{4x^2}+\frac{12x^3}{4x^2}+\frac{20x^2}{4x^2}

l(x)=2x^2+3x+5

5 0
3 years ago
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