Answer:
A) ERROR
B) ∠C = 26°
Step-by-step explanation:
Houston, We have a problem!!! too much information
If we had a legit triangle, the law of sines would hold
19/sin138 = 8/sin20
28.395 = 23.390
as this is NOT an equality, the triangle does not exist as described.
IF it did, we'd get different results depending on which set we used
∠F = 180 - 138 - 20 = 22°
Law of sines
19/sin138 = DE/sin22 ⇒ DE = 19sin22/sin138 = <u>10.63697...</u>
or
8/sin20 = DE/sin22 ⇒ DE = 8sin22/sin20 = <u>8.762211...</u>
If we attempt to use Law of cosines
DE² = 19² + 8² - 2(19)(8)cos22 = <u>11.9639...</u>
so really none is correct because we attempt to use trig calculations to a non-triangle.
12) AC² = 15² + 19² - 2(15)(19)cos120
AC = 29.51270...
29.51270 / sin120 = 15/sinC
C = arcsin(15sin120/29.51270) = 26.1142... <u>26°</u>
Answer:
y = 3x - 4
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line
m = 
= 
= 3
Note the line crosses the y- axis at (0, - 4) ⇒ c = - 4
y = 3x - 4 ← equation of line
Answer:
<u>complete question:</u>
If the height and base of the parallelogram shown are each decreased by 2 cm, what is the area of the new parallelogram?
A parallelogram with a base of 10 centimetres and a height of 8 centimetres
area = 48 cm²
Step-by-step explanation:
A parallelogram is quadrilateral with 4 sides formed by 2 pair of parallel lines. The area of a parallelogram is represented as follows :
area of parallelogram = B × H
where
B = breadth
H = height
According to the question the height and the base each reduced by 2 cm.
The new base = 10 - 2 = 8 cm
The new height = 8 - 2 = 6 cm
area = B × H
area = 8 × 6
area = 48 cm²
Answer:
x=7
Step-by-step explanation:
