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Andru [333]
2 years ago
8

State the domain & range!

Mathematics
2 answers:
vfiekz [6]2 years ago
8 0
Your domain is {x|x=-4,2,-3,0} and your range is {y|y=5,1,-2,-1}
anyanavicka [17]2 years ago
3 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

Domain: {-4, -3, 0, 2}

Range: {-2, -1, 1, 5}

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

  • The domain are all the given x-values in the function.
  • The range are all the given y-values of the function.
  • Usually in a table, the domain values are on the left and the range values are on the right.

⸻⸻⸻⸻

Knowing This:

Domain: {-4, -3, 0, 2}

Range: {-2, -1, 1, 5}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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Find the measures of the angles in ∆ABC if m∠A : m∠B : m∠C = 2:3:4.
g100num [7]

Answer:

A=40, B=60, C=80

Step-by-step explanation:

180/7 to find what "1" would be in the ratio then multiply 20*2, 20*3, 20*4.

3 0
3 years ago
Can someone find an equation for this because I am stuck on this. Thanks
Vera_Pavlovna [14]

Answer:

y = 11.5x - 18

Step-by-step explanation:

i created this table in desmos and then entered this equation underneath:

y₁ (tilda sign) = mx₁ + b

desmos will draw a line of best fit and provide the correlation coefficient, slope, and y-intercept

7 0
3 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation
aliina [53]

Answer:

a.  X~N(2,885, 651)

b.  0.086291

c.  0.00058

d.  3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting  the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

#substitute the given values in the formula to solve for P:

P(X

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0
3 years ago
223.6 x 0.0048 rough checks​
Norma-Jean [14]

Answer:

1.07328

Step-by-step explanation:

223.6 x 0.0048=1.07328

8 0
3 years ago
Total of 380 tickets were sold for the school play. they were either adult tickets or student tickets. there were 70 fewer stude
Bogdan [553]
Let the amount of adult tickets sold be x

Since the total of 380 tickets sold consists of the amount of adult tickets and the amount of children tickets that are 70 fewer:

x + (x - 70) = 380
2x - 70 =380
2x = 450
x = 225

Therefore, the amount of adult tickets sold is 225

8 0
3 years ago
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