Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).
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Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is . A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is .
The lateral surface area of the triangular pyramid is
cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
Y= 1/10x + 2/10 is what you are left with once the equation is simplified
Answer:
y = 3/2 x + 9
Step-by-step explanation:
take the two points and find slope :
12 - 3 / 2 - (-4) = 3/2
then use the slope and one of the points to find the y-intercept :
y = 3/2 x + b
3 = 3/2 * (-4) + b (Substitute)
3 = -6 + b (Multiplication)
3 + 6 = -6 + b + 6 (Addition)
b = 9
so, your final slope-intercept equation is :
y = 3/2 x + 9