Answer:
y^3/(27 x^3)
Step-by-step explanation:
Simplify the following:
((3 x)/y)^(-3)
((3 x)/y)^(-3) = (y/(3 x))^3:
(y/(3 x))^3
Multiply each exponent in y/(3 x) by 3:
(y^3)/((3 x)^3)
Multiply each exponent in 3 x by 3:
y^3/(3^3 x^3)
3^3 = 3×3^2:
y^3/(3×3^2 x^3)
3^2 = 9:
y^3/(3×9 x^3)
3×9 = 27:
Answer: y^3/(27 x^3)
Answer:
I guess (c) is your answer. thanks!!
The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0
<h3>How to determine the axis of symmetry?</h3>
The equation is given as:
y = 2x^2 + 3
Differentiate the above equation with respect to x
y' = 4x + 0
This gives
y' = 4x
Set the equation to 0
4x = 0
Divide both sides by 4
x = 0
Hence, the axis of symmetry is x = 0
Read more about axis of symmetry at:
brainly.com/question/1349456
Answer: Im sorry if im wrong but i think its G×4=2
Step-by-step explanation:I tried my best
8; 20/5=4, 4*2=8 so therefore it's 8 pounds
