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Lesechka [4]
1 year ago
10

Y = 2x^2 + 3 im looking for how to find the axis of symmetry

Mathematics
2 answers:
Maksim231197 [3]1 year ago
7 0

Answer:

The axis of symmetry is simply 0

Step-by-step explanation:

When you enter that equation on the graph the axis of symmetary is the line that goes straight throught the middle of it.

I inserted an image so you could understand a littler better. Hope this helps!

andre [41]1 year ago
4 0

The axis of symmetry of the quadratic equation y = 2x^2 + 3 is x = 0

<h3>How to determine the axis of symmetry?</h3>

The equation is given as:

y = 2x^2 + 3

Differentiate the above equation with respect to x

y' = 4x + 0

This gives

y' = 4x

Set the equation to 0

4x = 0

Divide both sides by 4

x = 0

Hence, the axis of symmetry is x = 0

Read more about axis of symmetry at:

brainly.com/question/1349456

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Harlamova29_29 [7]
Write it as a mixed fraction 7/5 = 1 2/5
5 0
3 years ago
Can someone answer question 2a and b only please
Mice21 [21]

Answer:

2a)  -2

b) 8

Step-by-step explanation:

<u>Equation of a parabola in vertex form</u>

f(x) = a(x - h)² + k

where (h, k) is the vertex and the axis of symmetry is x = h

2 a)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is 6, then

                 f(6) = 0

⇒ a(6 - 2)² - 6 = 0

⇒         16a - 6 = 0

⇒              16a = 6

⇒                  a = 6/16 = 3/8

So f(x) = 3/8(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒ 3/8(x - 2)² - 6 = 0

⇒      3/8(x - 2)² = 6

⇒           (x - 2)² = 16

⇒              x - 2 = ±4

⇒                   x = 6,  -2

Therefore, the other x-axis intercept is -2

b)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is -4, then

                 f(-4) = 0

⇒ a(-4 - 2)² - 6 = 0

⇒         36a - 6 = 0

⇒              36a = 6

⇒                  a = 6/36 = 1/6

So f(x) = 1/6(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒  1/6(x - 2)² - 6 = 0

⇒       1/6(x - 2)² = 6

⇒           (x - 2)² = 36

⇒              x - 2 = ±6

⇒                   x = 8,  -4

Therefore, the other x-axis intercept is 8

8 0
2 years ago
How do you solve -2(6x+3)=-27–5x ?
kvasek [131]
Hi!

Our goal is to isolate x on one side by doing the same operation on both sides.

First let's use the distribution property.
-2 x 6 = -12
-2 x 3 = -6
-12x - 6 = -27 - 5x

Add 6 to both sides
-12x - 6 + 6 = -27 + 6 - 5x
-12x = -21 - 5x

Add 5x to both sides
-12x + 5x = -21 - 5x + 5x
-7x = -21

Divide by -7 on both sides
-7x/-7 = -21/-7
x = 3

The answer is x = 3

Hope this helps! :)
8 0
3 years ago
Wyatt has 32 marbles in his collection. Twenty of his marbles are red, four are blue, and the
dmitriy555 [2]

Answer:

6 and 2/5

Step-by-step explanation:

20% of 32 is 6.4

4 0
3 years ago
What is the approximate length of a pendulum that takes 2.4 pi seconds to swing back and forth?
LuckyWell [14K]

Answer:

The length of the pendulum is 14.13 meters.

Step-by-step explanation:

The length of a pendulum is given by the formula, T = 2\pi \sqrt{\frac{L}{g} }, where T is the times period and L is the length of the pendulum.

Now, given that T = 2.4π seconds.

So, from the above equation, we get,

2.4\pi  = 2\pi  \sqrt{\frac{L}{g} }

⇒ \sqrt{\frac{L}{g}} = 1.2

⇒ \frac{L}{g} = 1.44 {We have the value of g as 9.81 m/sec²}

⇒ L = 1.44 × 9.81 = 14.13 meters. (Approx.)

Therefore, the length of the pendulum is 14.13 meters. (Answer)

3 0
3 years ago
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