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3 years ago

Is the point (2,4) a solution of y <= -4x + 12? HELP ASAP

Mathematics

1 answer:

Natasha2012 [34]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

y <= -4x + 12

(2,4) 4 <= -4*2 + 12 4<= 4 is true

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Object A has a mass of 12 g and a volume of 8 cm3. Object B has a mass of 20 g and a volume of 8 cm3. Which object has a greater

Andreyy89

Answer:

Obj B, by 1 g/cm^3

Step-by-step explanation:

Obj A = 12g / 8cm^3 = 3g / 2cm^3 = 1.5 g/cm^3

Obj B = 20g / 8cm^3 = 5g / 2cm^3 = 2.5 g/cm^3

2.5 - 1.5 = 1 g/cm^3

4 0

3 years ago

4/5 to 3/5 as a tenth of a percent

Rudik [331]

12/25 that will be the answer so its the percent time always helps.

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3 years ago

52. Kite ABCD has a longer diagonal AC with a length of 20in and a shorter diagonal BD with a length of 15in. The diagonals inte

sineoko [7]

7.5
the answer is 7.5

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3 years ago

Read 2 more answers

it cost $35 for one adult and two children to attend a show. It cost $60 for two adults and three children to attend the same sh

N76 [4]

Assume that,
adult = x
child = y

x+2y = 35 (1st equation)
2x+3y = 60 (2nd equation)
x = 35-2y (3rd equation)

Substitute 3 into 2 :

2(35-2y) + 3y =60
70-4y +3y = 60
y = 10

x+2y = 35
x+2(10) =35
x +20 =35
x = 15

One adult = $15

7 0

3 years ago

Find an equation for the perpendicular bisector of the line segment whose endpoints are (5,-9) and (1,3).

____ [38]

Given coordinates of the endpoints of a line segment (5,-9) and (1,3).

In order to find the equation of perpendicular line, we need to find the slope between given coordinates.

Slope between (5,-9) and (1,3) is :

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{3-\left(-9\right)}{1-5}$

$m=-3$

Slope of the perpendicular line is reciprocal and opposite in sign.

Therefore, slope of the perpendicular line = 1/3.

Now, we need to find the midpoint of the given coordinates.

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$=\left(\frac{1+5}{2},\:\frac{3-9}{2}\right)$

$=\left(3,\:-3\right)$

Let us apply point-slope form of the linear equation:

y-y1 = m(x-x1)

y - (-3) = 1/3 (x - 3)

y +3 = 1/3 x - 1

Subtracting 3 from both sides, we get

y +3-3 = 1/3 x - 1 -3

3 0

3 years ago