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-Dominant- [34]
3 years ago
7

Sidewalk chalk comes in a pack of 24 for $2.59 Bruce takes $20 to the store and purchases as many packs of sidewalk chalk as he

can with the money
After purchasing sidewalk chalk how much change your Bruce have assuming no sales tax?

note: type your answers decimal number
Mathematics
1 answer:
siniylev [52]3 years ago
7 0

Answer:

He has $1.87 change left after purchasing 7 packs of chalk.

Step-by-step explanation:

20/2.59 = 7.722 approx.

So Bruce can purchase 7 packs of chalk at $2.59 each.

Change left

= 20 -7*2.59

= $1.87

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Fewer young people are driving. In year A, 67.9% of people under 20 years old who were eligible had a driver's license. Twenty y
aleksley [76]

Answer:

                                 Case a                               Case b

margin of error       0.0216                                   0.0231

Interval estimate   (0.7016 , 0.6795)                (0.5031 , 0.4569)

margin of error is not same in both cases.

Step-by-step explanation:

a

At 95% confidence interval the interval estimate of number of 20 year old drivers in year A can be computed as

  p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.68 ± 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.7016 , 0.6795

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

= 1.96 \sqrt{\frac{0.68(1-0.68)}{1800} }

= 0.0216

b

At 95% confidence interval the interval estimate of number of 20 year old drivers in year B can be computed as

p'  ±  z  \sqrt{\frac{p'(1-p')}{n} }

= 0.48 ± 1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

=  0.5031 , 0.4569

the margin of error can be written as

z  \sqrt{\frac{p'(1-p')}{n} }

=  1.96 \sqrt{\frac{0.48(1-0.48)}{1800} }

= 0.0231

c

Sample size is same in case A and B but proportion is different in both cases so margin of error is different in both cases

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A and C are vertical angles.


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