I would start with the standard form equation of the parallel line.
.. 5x -2y = 5(-2) -2(3) = -16
Then solve for y.
.. 2y = 5x +16 . . . add 2y+16; then divide by 2 for the next equation
.. y = (5/2)x +8 . . . . . . . corresponds to selection (B)
The perimeter is everything added up, since its not a square then you add not multiply. 24+24=48 and 16+16=32, add 32 and 48 and get 80. Answer:80
Answer:
It will take him about 13 houses to sell the 5 candy bars.
Pat has an 18% chance of selling his last candy in the 11th house.
Step-by-step explanation:
Since Pat is required to sell candy bars to raise money for the 6th grade field trip, and there is a 40% chance of him selling a candy bar at each house, and he has to sell 5 candy bars in all, to determine the number of houses it takes and determine the probability he sells his last candy bar at the 11th house, the following calculations must be performed:
5 / 0.40 = X
12.5 = X
So, it will take him about 13 houses to sell the 5 candy bars.
5/11 = X
0.45 = X
0.45 x 0.4 = 0.18
Thus, Pat has an 18% chance of selling his last candy in the 11th house.
(a) The 150 gallons of empty space in the tank are being filled at the rate of 1 gallon per minute. The tank will be filled after 150 minutes.
(b) s(0) = 5
.. s'(t) = -2s(t)/(50 +t)
Q1 of company A = 2.5
Q3 of company A = 8
Interquatile range = (Q3 - Q1)/2 = (8 - 2.5)/2 = 5.5/2 = 2.75
Q1 of company B = 2
Q3 of company B = 5.5
Interquatile range = (5.5 - 2)/2 = 3.5/2 = 1.75
Therefore, t<span>he interquartile range for Company A employees is 2 more than the interquartile range for Company B employees.</span>
