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sashaice [31]
3 years ago
8

I will give brainliest

Mathematics
2 answers:
Karolina [17]3 years ago
8 0
The large scoop holds 48 units.
36/0.75 = 48
kobusy [5.1K]3 years ago
4 0

Answer:

Large scoop holds 48 units.

Step-by-step explanation:

Large:  x

Small:  .75x = 36

               x = 48 units

You might be interested in
Find principal of a loan at 11% for 5 years with $426.25 simple interest
Ahat [919]

Answer:

P=775

Step-by-step explanation:

The Simple Interest Equation is A = P(1 + rt)

where

A = Total Accrued Amount (principal + interest)

P = Principal Amount

I = Interest Amount

t = Time Period involved in months or years

In this case, we do not know the values ​​of the equation (A and P), but we know the amount of interest accrued

If we define our principal whit this formula, we are able to know the rest of the values:

A-P= interest

clearing

A=interest+P

replacing

426.25 + P = P (1+(0.11(5))

Solving

426.25+P=1.55P

P-1.55P=-426.25

-0.55P=-426.65

P=\frac{-426.25}{-0.55}

P=775

7 0
3 years ago
What is the unit rate $1.79 for 15 oz rounded to nearest tenth
ser-zykov [4K]

Answer:

$0.119... per oz, or 0.1

Step-by-step explanation:

$.179 ÷ 15 = 0.119...

Now round to the nearest tenth, and you get 0.1.

8 0
2 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
What is the equation of the line written in general form?
Irina18 [472]
I think its b or c but my best guess would be b
7 0
3 years ago
3. 1/2 + 1 1/3 Please answer quick!!!!!!!!!!!!!!!!!! Step by step explanation with answer!
Law Incorporation [45]

Answer: 1/2+11/3 = 4.1*6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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