Answer:
5
Step-by-step explanation:
12x12-13x13=b2
144-169=b2
25
=5
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
-2837162/3
Step-by-step explanation:
5674324/-6
-5674324/6
-2837162/3
Answer:
x = -1 or x = -10
Step-by-step explanation:
x^2 + 11x + 10 = 0
x^2 + 10x + x + 10 = 0
x(x + 10) + 1(x + 10) = 0
(x + 1) (x + 10) = 0
x + 1 = 0 or x + 10 = 0
x = -1 or x = -10