Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Uhmm mm I think it's true, and so does Siri hahahah
He spent $9.50 in total. To find this answer, you write the equation 2(9.95) + 3(1.20). You would distribute getting 5.90 + 3.60= $9.50.
For both of these questions you want to raise every part to the 4th or 2nd power. Just remeber that a power raised to a power is just multiplied.
3.)
3^4 = 3×3×3×3 = 9×9 = 81
x^4 = 1×4 = 4 so x^4
2^4 = 2×2×2×2 = 4×4 = 16
so

4.)
2^2 = 2×2 = 4
5^2 = 5×5 = 25
(n^9)^2 = 2×9 = 18 so n^18
so

Hope this helps!
Answer:
-4
Step-by-step explanation:
Use PEMDAS