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3 years ago

What is the answer to -0.8x+40-8x-35

Mathematics

2 answers:

pashok25 [27]3 years ago

7 0

Answer:

25/44

Step-by-step explanation:

-0.8x+40-8x-35

-8.8x+5

-8.8x=-5

Minus sign cancel on both side

X=5/8.8

X=50/88

X=25/44

So value of x is 25/44

vaieri [72.5K]3 years ago

6 0

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

Write your answer as an integer or as a decimal rounded to the nearest hundredth.

irina [24]

Answer:

Step-by-step explanation:

USing SOH CAH TOA

sin theta = opposite/hypotenuse

sin <X = WV/VX

sin <X = 8/9

<X = arcsin(8/9)

<X = arcsin(0.8889)

<X = 62.7 degrees

Hence the value of x is approximately 63degrees

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2 years ago

A scale drawing of a school bus has a scale of 12 inch to 5 feet. If the length of the school bus is 412 inches on the scale dra

Thepotemich [5.8K]

Answer:

actual length = 171.67 ft.

Step-by-step explanation:

scale of school bus drawing is 12 in. to 5 ft.

if the length of a school bus drawing is 412 in.

5 ft

the actual length is = 412 in x --------

12 in

actual length = 171.67 ft.

7 0

2 years ago

Create a matrix for this system of linear equations, The determinant of the coefficient matrix is

marin [14]

Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation: The given system of linear equations is :

$2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

$D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.$

Now, from equations (ii) and (iii), we have

$x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

$2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.$

From equations (iv) and (v), we get

$y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.$

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

3 0

3 years ago