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Alinara [238K]
3 years ago
10

Jada is evaluating 8 × 3 × 4. She doesn't know the product of 24 and 4 off the top of her head, so she decides to multiply 3 by

4 first. Which property is Jada using? associative property distributive property commutative property
Mathematics
2 answers:
siniylev [52]3 years ago
7 0

Answer:

plz explain correctly please

anzhelika [568]3 years ago
7 0

Answer:

It would be Associative because she is Multiplying in different groups, so for example you said that she didn't know what 24 x 4 was so then she took 3 x 4 so she just regrouped the numbers to get the answer needed.

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(-4)(-2)= 8
8(-5)= -40
Answer: -40
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I think it would be 120
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What is the equation of the line that passes through the point 4, -6 and has a slope of -3
zheka24 [161]
Y = mx + b. Use this equation for most linear functions. Enter the information that is given to you.
- 6 =  - 3(4) + b
Multiply the -3 and 4 to get 12.
-6 =  - 12 + b
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\frac{ - 6}{ - 12}  =   \frac{ - 12}{ - 12}  + b
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Find the volume of the cylinder.<br> Either enter an exact answer in terms of π or use 3.14
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A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =
tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

f(x)=-16x^2+64x+5

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

10=-16x^2+64x+5

Subtracting 10 from both sides:

-16x^2+64x-5=0

For simplicity, divide both sides by -1:

16x^2-64x+5=0

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Substitute:

\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}

Evaluate:

\displaystyle x=\frac{64\pm\sqrt{3776}}{32}

Simplify the square root:

\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}

Therefore:

\displaystyle x=\frac{64\pm8\sqrt{59}}{32}

Simplify:

\displaystyle x=\frac{8\pm\sqrt{59}}{4}

Approximate:

\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0
2 years ago
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