All categories

3 years ago

How many square inches are in 60 square feet

Mathematics

2 answers:

jasenka [17]3 years ago

5 0

<h2>Answer</h2>

8640 square inches

<h2>Explanation</h2>

To solve this, we are going to take advantage of the fact that 1 square foot is equal to 144 square inches so we can create a suitable conversion fraction.

Since we want to convert from square feet from inches, the denominator of our conversion fraction will be square feet so we can cancel those out and get the result in square inches:

$60square.feet*\frac{1144square.inches}{1square.fett} =60*144square.inches=8640square.inches$

There are 8640 square inches in 60 square feet

cricket20 [7]3 years ago

5 0

Answer:

8640

Step-by-step explanation:

144 sq in are in 1 sq foot, so times that by 60, and you get 8640. Hope this helps :)

You might be interested in

What is the width of a rectangle with an area of 5/8 inches and the length of 10 inches?

Nimfa-mama [501]

A = LW......W = A/L
A = 5/8
L = 10

W = (5/8) / 10
W = 5/8 * 1/10
W = 5/80 = 1/16

3 0

4 years ago

Find the distance between the points H and C.<br><br> A) 0 <br> B) 2 <br> C) 4 <br> D) 8

RSB [31]

Answer:

Step-by-step explanation:

1.b

2.c

3.d

4.g

6 0

3 years ago

Please help me it's urgent

Stels [109]

Step-by-step explanation:

−2p−100=(−10)

−2(−10)−100 [Putting p=−10]

=100+20−100=20.

ᴍᴀʀᴋ ᴀꜱ ʙʀᴀɪɴʟɪᴇᴀꜱᴛ

7 0

3 years ago

Scateboard cost Rs450each in my local store,The shop keeper says if I buy 1 I can buyanother for only 7/9 of the normal price,ho

Whitepunk [10]

Answer:

the cost will be Rs 350

Step-by-step explanation:

The Scateboard cost Rs 450 each in the local store,The shop keeper says if I buy 1 I can buy another for only $\frac{7}{9}$ of the normal price. We are asked to determine the cost of a second scateboard .

Hence the cost will be $\frac{7}{9}$ of the normal cost that is

$\frac{7}{9} \times 450$

$7 \times 50$

$350$

the cost will be Rs 350

6 0

4 years ago

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

3 years ago